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Fiesta28 [93]
2 years ago
8

Ghfghfghfhghfhfghfhfhfhfghfgh

Physics
2 answers:
snow_tiger [21]2 years ago
7 0

Answer:

hello

Explanation:

Ulleksa [173]2 years ago
4 0

Explanation:

guxxxhchclcyffktx

oye hoye thanks for point ✌✌✌✌✌

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Muscles that are fatigued ____. A. Are injured , B. Should always be rested , C. Can sometimes be exercised further D. Should be
Lorico [155]

Answer:

<u>B. Should be rested</u>

Explanation:

That is the only reasonable answer.

5 0
3 years ago
Read 2 more answers
Which switch configuration creates a short circuit?
lara31 [8.8K]
I think the answer would be Switch 1 open; switches 2, 3, and 4 closed. It is letter D. This will happen when there is a low resistance and a high circuit so from the choices above, when two bulbs are open and one bulb is close, so there is a low resistance and high voltage.
6 0
3 years ago
When riding your skateboard you crash into a curb, the skateboard stops, you continue moving forward. Which law of motion is bei
Olenka [21]
You continue moving forward, and you HOPE that some of the other
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7 0
3 years ago
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
LenaWriter [7]

Answer:

vf = √(vi²+2*(F/m)*D)

Explanation:

Given

Mass of the particle: M

Initial speed of the particle: vi

Force: F

Distance: D

We can apply the formula

F = M*a   ⇒    a = F/m

then we use the equation

vf = √(vi²+2*a*D)

⇒  vf = √(vi²+2*(F/m)*D)

6 0
3 years ago
A frog hops 5m east and 2m north. What is the magnitude of the frogs total displacement in m?
TiliK225 [7]

As per the question a frog jumps 5 m towards east.

Frog again jumps 2 m north.

Let the displacement along east is denoted by vector A and the displacement towards north is denoted as vector B.

Hence magnitude of A = 5 m

           Magnitude of B = 2 m

We are asked to calculate the total displacement.

Here the angle between them is 90 degree as A is towards east and B is towards north.

As per parallelogram law of vector addition,the magnitude of total displacement [R] will be-

                            R=\sqrt{ A^{2} +B^{2}+2AB\cos\theta}

                            =\sqrt{ 5^{2}+ 2^{2}+2*5*2 cos 90}

                            =\sqrt{25+4+0} m  [cos90= 0]

                            =\sqrt{29} m

                            = 5.38516 m   [ans]

                     


7 0
3 years ago
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