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Fiesta28 [93]
2 years ago
8

Ghfghfghfhghfhfghfhfhfhfghfgh

Physics
2 answers:
snow_tiger [21]2 years ago
7 0

Answer:

hello

Explanation:

Ulleksa [173]2 years ago
4 0

Explanation:

guxxxhchclcyffktx

oye hoye thanks for point ✌✌✌✌✌

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As a stunt for movie two cars are to collide with each other head on. The two cars are initially 125 apart. Car A is heading str
Tema [17]

Answer:

3.39724 seconds

23.0824792352 m, 101.917520765 m

13.58896 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The equation of motion will be

s=ut+\dfrac{1}{2}at^2\\\Rightarrow 125=30\times t+\dfrac{1}{2}\times 4\times t^2\\\Rightarrow 2t^2+30t-125=0\ m

t=\frac{5\left(\sqrt{19}-3\right)}{2},\:t=-\frac{5\left(3+\sqrt{19}\right)}{2}\\\Rightarrow t=3.39724, -18.39724

The time at which the cars collide is 3.39724 seconds

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 3.39724^2\\\Rightarrow s=23.0824792352\ m

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

v=u+at\\\Rightarrow v=0+4\times 3.39724\\\Rightarrow v=13.58896\ m/s

The speed of car B is 13.58896 m/s

4 0
3 years ago
The product of an emf and a charge moving through it is:
liq [111]
The answer is to your question is force
3 0
3 years ago
What is the independent variable on this graph??
Veronika [31]
Temperature. X-axis is always the independent variable.
3 0
4 years ago
Read 2 more answers
How does the mass of an object change the gravitational pull on two objects in a system? How does the distance between objects i
LuckyWell [14K]

Answer:The greater the mass, there greater then gravitational pull on their objects.

There greater the distance,the lower the gravitational pull between the object

Explanation:

Gravitational pull(force) is directly proportional to the products Of The masses. therefore if the mass increase,the gravitational pull(force) also increases.

Gravitational pull(force) is inversely proportional to distance.if the distance between the objects increases,the gravitational pull(force) decreases .

4 0
3 years ago
What is the gauge pressure (in atm) in a 25.0°C car tire containing 3.81 mol of gas in a 31.5 L volume? (Enter your answer to at
bagirrra123 [75]

Answer:

Explanation:

Given

Temperature of gas T=25^{\circ}C\approx 298\ K

Volume of gas V=31.5\ L\approx 31.5\times 10^{-3}\ m^3

no of moles of gas n=3.81\ mol

Using Ideal gas Equation to find the Pressure of gas

PV=nRT

where P=Absolute Pressure

V=Volume

R=Universal gas constant

T=Temperature

P\times 31.5\times 10^{-3}=3.81\times 8.314\times 298

P=\frac{3.81\times 8.314\times 298}{31.5\times 10^{-3}}

P=299.66\ kPa

And we know Atmospheric Pressure is 101.325\ kPa

Therefore Gauge pressure is given by

P_{gauge}=P-P_{atm}

P_{gauge}=299.66-101.325

P=198.34\ kPa

4 0
3 years ago
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