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3 years ago

Plz help me out in need u to help me

Physics

2 answers:

Feliz [49]3 years ago

8 0

Answer:

First and third one

Explanation:

Took test, and it can be the other ones because they dont make any sense

Westkost [7]3 years ago

6 0

1 and 3...... I have done this before

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The spacing between the plates of a 1.0 μF capacitor is 0.050 mm. a) What is the surface area of the plates? b) How much charge

nataly862011 [7]

Answer:

(a) surface area of the plate will be equal to $1.129m^2$

(b) Charge on the capacitor is equal to $1.5\times 10^{-6}C$

Explanation:

We have given spacing between the plates d = 0.05 mm = $5\times 10^{-5}m$

Value of capacitance $C=1\mu F=10^{-6}F$

(A) Capacitance of a parallel plate capacitor is equal to $C=\frac{\epsilon _0A}{d}$

So $10^{-6}=\frac{8.85\times 10^{-12}\times A}{10^{-5}}$

$A=1.129m^2$

So surface area of the plate will be equal to $1.129m^2$

(B) It is given that capacitor is charged by 1.5 volt

So voltage V = 1.5 volt

Charge on the capacitor is equal to $Q=CV$

So $Q=1.5\times 10^{-6}C$

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How far does light travel in the time it takes sound to travel 1 cm in air at 20°c?

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The speed of sound at $20^{\circ}C$ is approximately v=343 m/s. The distance covered by the sound wave is
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