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Gelneren [198K]
2 years ago
13

The table shows the number of minutes Jalen talks on his mobile phone and the cost of the phone calls. Jalen's Mobile Phone Cost

Number of minutes, X 150 220 250 275 x Cost, y $7.50 $11.00 $12.50 $13.75 If the cost varies directly with the number of minutes Jalen talks on the phone, which equation represents the variation? O y = 0.05% O y = 20x O y = 157.58 O y = 1125x Save and Exit Net Submit Mark this and return​
Mathematics
1 answer:
Dima020 [189]2 years ago
4 0

Answer: y=0.5x

Step-by-step explanation: hope this would be helpful ∵∵∵∵∵∵∵∵∴∴∴∴∴∴∴∴∴

THUNDERBOLT
2 years ago
it's 0.05.
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Step-by-step explanation:

a) 12\dfrac{1}{2}=\dfrac{25}{2}\\\\\dfrac{25}{2*100}*480= \dfrac{1}{2*4}*480 = 60 \ cm\\\\b) \dfrac{3}{4*100}*1200= 3*3 = 9 \ Rs.

7 0
2 years ago
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Evaluate.
lys-0071 [83]

Answer:

  361/900

Step-by-step explanation:

  \left(-\dfrac{1}{6}+0.6\left(-\dfrac{1}{3}\right)+1\right)^2=\left(-\dfrac{1}{6}-0.2+1\right)^2\\\\=\left(1-\left(\dfrac{1}{6}+\dfrac{1}{5}\right)\right)^2=\left(1-\dfrac{5+6}{6\cdot5}\right)^2=\left(\dfrac{19}{30}\right)^2=\boxed{\dfrac{361}{900}}

8 0
2 years ago
The United States Postal Service charges a
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6 0
3 years ago
PLEASE HELP!!!!!!! A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a
Marianna [84]

Answer:

The answer to your question is car 1 = 30 gal and car 1 = 20 gal

Step-by-step explanation:

car 1 = a

car 2 = b

Efficiency of car 1 = 35 mi/gal

Efficiency for car 2 = 20 mi/gal

Total distance = 1450

Total gas consumption = 50 gal

Equations

                          35a + 20b = 1450            ------- (I)

                             a   +     b =  50               ------- (II)

Solve by elimination

Multiply equation II by -35

                          35a  + 20b  = 1450

                         -35a  - 35b   = -1750

Simplify

                            0    - 15b    =  -300

Solve for b

                                        b =  -300/-15

Result

                                        b = 20

Substitute b in equation II to find a

                               a +  20  = 50

Solve for a

                               a  = 50 -20

Result

                               a  = 30

4 0
3 years ago
4x + 8y=20<br> 3x+6y=15<br> solve this system of equations
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4x=20-8y

x=5-2y now use this value of x in the second equation...

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15=15  This is true for any y or x value.

So there are infinitely many solutions as the two equations describe the same line.
5 0
3 years ago
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