Answer:
Step-by-step explanation:

Answer:
361/900
Step-by-step explanation:

Answer:
your answer would to your question is d
Answer:
The answer to your question is car 1 = 30 gal and car 1 = 20 gal
Step-by-step explanation:
car 1 = a
car 2 = b
Efficiency of car 1 = 35 mi/gal
Efficiency for car 2 = 20 mi/gal
Total distance = 1450
Total gas consumption = 50 gal
Equations
35a + 20b = 1450 ------- (I)
a + b = 50 ------- (II)
Solve by elimination
Multiply equation II by -35
35a + 20b = 1450
-35a - 35b = -1750
Simplify
0 - 15b = -300
Solve for b
b = -300/-15
Result
b = 20
Substitute b in equation II to find a
a + 20 = 50
Solve for a
a = 50 -20
Result
a = 30
4x=20-8y
x=5-2y now use this value of x in the second equation...
3(5-2y)+6y=15
15-6y+6y=15
15=15 This is true for any y or x value.
So there are infinitely many solutions as the two equations describe the same line.