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3 years ago

5

The Cholula Pyramid in Mexico has a height approximately ퟐퟏퟕfeet and a base approximately ퟏퟒퟕퟔfeet by ퟏퟒퟕퟔfeet. The Cheops Pyram

id (part of the Great Pyramids) is taller with an approximate height of ퟒퟖퟎfeet but with a ퟕퟓퟓfeet by ퟕퟓퟓfeet base. Determine which pyramid has the most volume

1 answer:

larisa [96]3 years ago

6 0

Answer:

The Cholula Pyramid has a bigger volume out of the two.

Step-by-step explanation:

The volume of a Pyramid is V=1/3Bh

Volume of the Choulula = 1/3 (2,178,576)(217)= 157,583,664

Volume of The Cheops Pyramid = 1/3 (570,025)(480)=91,204,000

157,583,664 is greater than 91,204,000

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Think about your previous math courses. Identify one tope that you learned about which

saw5 [17]

The answer for this question I don’t think could be answered by anyone but yourself. To help you figure this out, just simply think about all of the math courses you’ve had previous to your current course and think about which course you did best in.

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3 years ago

The product of 3 and a number x is 23 . What is the value of x?

Scrat [10]

I believed there's a typo in your question
<span>The product of 3 and a number x is 2/3
if so
</span>3x = 2/3
x = 2/3 * 1/3
x = 2/9

answer
x = 2/9

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4 years ago

The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged

Temka [501]

Answer:

a) 0.283 or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z= $\frac{X-M}{s}$ where

X is the left atrial diameter value we are looking for its z-score

M is the mean left atrial diameter of healthy children (26.7 mm)

s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*= $\frac{24-26.7}{4.7}$ ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*= $\frac{32-26.7}{4.7}$ ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)= $\frac{30-26.7}{4.7}$ ≈ 0.702

z(25)= $\frac{25-26.7}{4.7}$ ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84= $\frac{X-26.7}{4.7}$ solving this equation for X we get X=30.648

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3 years ago

Look at the following graph of the given equation. Determine whether the equation is a function. Explain why or why not.

Vadim26 [7]

The equation $y=2x+2$ is a function

Explanation:

Given that the graph contains the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$

We need to determine whether the equation $y=2x+2$ is a function.

To determine the equation is a function, let us substitute the coordinates in the equation and check whether it satisfies the equation.

Let us substitute the coordinate $(-1,0)$ in the equation $y=2x+2$

Thus, we have,

$0=2(-1)+2$

$0=-2+2$

$0=0$

Thus, the coordinate $(-1,0)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(0,2)$ in the equation, we have,

$2=2(0)+2$

$2=2$

Thus, the coordinate $(0,2)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(1,4)$ in the equation $y=2x+2$

$4=2(1)+2$

$4=4$

Thus, the coordinate $(1,4)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(2,6)$ in the equation, we get,

$6=2(2)+2$

$6=6$

Thus, the coordinate $(2,6)$ satisfies the equation $y=2x+2$

Hence, the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$ satisfies the equation $y=2x+2$

Thus, the equation $y=2x+2$ is a function.

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3 years ago

What is the area of the parallelogram QRST?

jonny [76]

$\text{Area of parallelogram QRST} = QR \times TU = 20 ~in \times 18~in =360 in^2$

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2 years ago