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Brums [2.3K]
4 years ago
13

I need help answering 14 and 15

Chemistry
1 answer:
Debora [2.8K]4 years ago
4 0

Answer:

14 is D and 15 is C

Explanation:

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In the quantum mechanical model, what two words do they use to describe<br> particles?
miskamm [114]

Answer:

This question is incomplete

Explanation:

This question is incomplete but one can assume the answer from the definition of quantum mechanics. Quantum mechanics is the science that describes particles in nature at the atomic and subatomic particle (electron, proton and neutron) level. Thus it can be assumed that atoms and subatomic particles are used to broadly describe particles.

5 0
3 years ago
An aqueous solution has a molality of 3. 64 kcl. what is the the mass percent of kcl in the solution? enter your answer to three
Sliva [168]

The mass percentage of KCl solution is 21.34%

Calculation,

Given molality of KCl aqueous solution =  3. 64  m =  3. 64 mole/ Kg

It means 3. 64 mole of solute present in 1Kg of solvent

or ,  3. 64 mole of solute present in 1000 g of solvent ( water )

Mass of solute ( KCl ) =  3. 64 mole×74.55 g/mole =271.3 g

The total mass of solution ( KCl + water ) = 271.3 g + 1000 g = 1271.3 g

Mass percentage is equal to percentage of mass of solute present in total mass of solution.

Mass percentage = 100×271.3 g/1271.3 g = 21.34%

to learn more about mass percentage

brainly.com/question/27108588

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5 0
2 years ago
Are two double bonds in<br> uble dash.<br> :0=C=O<br> NO2-
LenaWriter [7]

Answer:

Yes

Explanation:

There are in double dash :) ( = )

5 0
3 years ago
Read 2 more answers
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
3 years ago
Four properties of water are listed.
vichka [17]

Explanation:

Physical property

1- Water is colorless and odorless in its pure form

6 0
3 years ago
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