PLEASE HELP ASAP!! I AM PRETYY SURE THE ANSWER IS 10 BUT I NEED THE STEPS

Mr. Robinson took a nap 12 out of the 15 days of his vacation what what percent of Mr. Robinsons vacation did he nap

jonny [76]

Answer:

80%

Step-by-step explanation:

convert to percent:

$\frac{12}{15}*100 = 80 percent$

8 0

2 years ago

Which of the following represents a geometric sequence?

grin007 [14]

Answer:

Option 1 is a geometric sequence.

I 1/4, 1/4, 1/4, 1/4

II 1/4, 1/5, 1/6

III 1/4, 1, -4, 1/6

IV 1/4, -4, 1/4, -4

For any geometric sequence there should be a common ratio

To find common ratio we divide consecutive terms

lets check option I

I 1/4, 1/4, 1/4, 1/4

When we divide 1/4 by 1/4 we will get 1

Same 1 for other two terms, so common ratio is 1

Hence the first option is a geometric sequence

Please Mark Brainliest If This Helped!

6 0

2 years ago

How is 0.136¯ written as a fraction in simplest form? Enter your answer in the box.

nignag [31]

The answer is 3/22
I see the answer 17/125 around a lot, and that's not wrong but I don't think it's simplified enough

7 0

4 years ago

Read 2 more answers

The exponential model A=429e 0.024t describes the population, A, of a country in millions, t years after 2003. Use the model t

d1i1m1o1n [39]

Answer:

Year 2,590

Step-by-step explanation:

In this question, we are asked to calculate the year at which the population of a country will be a certain amount given the exponential equation through which the equation proceeds.

Let’s rewrite the exponential function;

A = 429e^0.024t

Now here, our A is 559,000,000

t is unknown

Let’s substitute this value of A in the exponential equation;

559,000,000 = 429 * e^0.024t

559,000,000/429 = e^0.024t

1,303,030.303030303 = e^0.024t

Let’s take the logarithm of both sides to base e, we have;

ln(1,303,030.303030303) = ln(e^0.024t)

14.08 = 0.024t

t = 14.08/0.024

t = 587 years

Now, we add this to year 2003 and this gives year 2590

7 0

4 years ago

Given the function:

anyanavicka [17]

You are correct. The answer is choice D

The only way for g(x) to be differentiable at x = 0 is for two things to happen
(1) g(x) is continuous at x = 0
(2) g ' (x) is continuous at x = 0

To satisfy property (1) above, the value of b must be 1. This can be found by plugging x = 0 into each piece of the piecewise function and solving for b.

So the piecewise function becomes
$g(x) = \begin{cases}x+1 \ \text{ if } \ x \ < \ 0\\ \cos(x) \text{ if } \ x \ge 0\end{cases}$
after plugging in b = 1

--------------------------------

Now differentiate each piece with respect to x to get
$g'(x) = \begin{cases}1 \ \text{ if } \ x \ < \ 0\\ -\sin(x) \text{ if } \ x \ge 0\end{cases}$
The first piece of g ' (x) is always going to be equal to 1. The second piece is equal to zero when x = 0
Because -sin(x) = -sin(0) = 0

So there's this disconnect on g ' (x) meaning its not continuous

Therefore, the value b = 1 will not work.

So there are no values of b that work to satisfy property (1) and property (2) mentioned at the top.

5 0

3 years ago