We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.






Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is
.
Therefore, the radius of given circle would be 18 cm.
Answer:
x<11
Step-by-step explanation:
x−4(|−2|)<3
Simplifies to:
x−8<3
Let's solve your inequality step-by-step.
x−8<3
Step 1: Add 8 to both sides.
x−8+8<3+8
x<11
Answer:
Q=33/10-r/10 R=33−10q
Step-by-step explanation:
Espero que sea correcto para ti también puedes hacerme más inteligente si es correcto
Answer:
5
Step-by-step explanation:
what do you mean ?? its already written there
Answer:
A: f(x)=2x^2 +12x +10
B: f(0) = 10
Step-by-step explanation:
<u>Part A</u>:
f(0) is a constant in the equation if the form is such that for x=0, all terms are zero except one of them. Standard form is one such form. This is the equation in standard form:
f(x) = 2x^2 +12x +10
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<u>Part B</u>:
f(0) = 0 + 0 + 10
f(0) = 10