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Maru [420]
3 years ago
14

Let's say you cut open a log of wood with an axe, what type of simple machine are you using? Does it matter how sharp it is?

Physics
2 answers:
slamgirl [31]3 years ago
8 0

yes it matters because if it's not sharp it would take all day

katen-ka-za [31]3 years ago
7 0

Answer:

an axe is a type of machine called a wedge. it does matter how sharp your axe is. if your axe is not sharp then you will have a harder time cutting wood.

Explanation:

You might be interested in
The common uses of radioactive elements in health care.
viva [34]

Answer: I-131, P-32, Sr-90, Co-60 & Technetium.

Explanation: Isotopes like I-131 are used to diagnose goiter in thyroid gland and isotopes like P-32 Sr-90 are used for treatment of skin cancer and Co-60 for cancer and technetium is used to monitor bone growth.

4 0
3 years ago
Two long, parallel wires are attracted to each other by a force per unit length of 305 µN/m. One wire carries a current of 25.0
kykrilka [37]

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

\frac{F}{L} = \frac{kl_1l_2}{d}

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is 305*10^{-6}N/m then we have

l_2 = \frac{F}{L} (\frac{d}{kl_1})

l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})

l_2 = 28.67A

Considering the B is zero at

y = y_1

\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}

\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}

y_1 = 0.25m

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

5 0
4 years ago
The lightest and heaviest flying birds are the bee hummingbird of Cuba, which weighs about 1.6 grams, and the great bustard of E
VMariaS [17]

Answer:

for the birds to be able to stay vertical in flight without falling down to earth, they must produce a lift that will counteract their weight

for the small bee humming bird,

mass = 1.6 g = 1.6 x 10^{-3}  kg

weight of the bird under acceleration due to gravity = mg

where g = acceleration due to gravity = 9.81 m/s^2

weight of the bird = 1.6 x 10^{-3}  x 9.806 = 0.0156 ≅ 0.016 N

for this bird to maintain flight, the least lift upward, it must generate must be equal to its weight downwards, i.e

lift = weight

therefore,

lift = <em>0.016 N</em>

<em></em>

For the bustard of Europe and Asia,

mass = 21 kg

weight of the bird under acceleration due to gravity = mg

weight of the bird = 21 x 9.806 = 205.9 N

lift = weight =  <em>205.9 N</em>

<em></em>

<em>lift generated is proportional to the wing surface area according to the lift equation</em>

L = Cs x p x \frac{v}{2} x S

where L = lift

C = lift coefficient

p = density of air

v = relative velocity of bird and air

S = surface are of the wing.

<em>The great bustard will have a proportionally larger wing area to hold its weight in flight</em>

<em></em>

7 0
3 years ago
When talking about Acceleration ,what is significant about the about the sign(+ or -)?​
OLEGan [10]

Answer:

Acceleration at its most basic is the act of increasing your running speed. From a standing start (or blocks), you explode into action. If you’re already running, you pick up the pace. Acceleration continues until you can no longer increase your speed, at which point you achieve maximum velocity (top-end speed). Acceleration seems simple enough. The plus means your increasing speed, the k=minus means your decreasing in speed.

Explanation:

5 0
3 years ago
A spherically symmetric charge distribution has a charge density given by ρ = a/r , where a is constant. Find the electric field
Airida [17]
Charge dQ on a shell thickness dr is given by 

dQ = (charge density) × (surface area) × dr 

dQ = ρ(r)4πr²dr 

∫ dQ = ∫ (a/r)4πr²dr 

∫ dQ = 4πa ∫ rdr 

Q(r) = 2πar² - 2πa0² 

Q = 2πar² (= total charge bound by a spherical surface of radius r) 

Gauss's Law states: 

(Flux out of surface) = (charge bound by surface)/ε۪ 

(Surface area of sphere) × E = Q/ε۪ 

4πr²E = 2πar²/ε۪ 

<span>E = a/2ε۪


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
3 0
3 years ago
Read 2 more answers
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