Does the uphill or downhill direction matter to the speed of the marble, or is the height the only contributing variable?

Please help solving this physics question

sp2606 [1]

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False.
True
True
False

4 0

3 years ago

Which is most likely the length of a student’s textbook?

UkoKoshka [18]

For this case, what we must do is to rewrite these measurements in the same unit in order to compare them.

By writing the measurements in meters we have:

$30 mm = (30) * (\frac{1}{1000}) = 0.030 m$

$30 cm = (30) * (\frac{1}{100}) = 0.30 m$

$30 dm = (30) * (\frac{1}{10}) = 3 m\\30 Hm = (30) * (100) = 3000 m$

Therefore, physically the correct measure is:

$0.30 m = 30 cm$

Answer:

the length of a student's textbook most likely is:

30 centimeters

3 0

3 years ago

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The x vector component of a displacement vector has a magnitude of 86.2 m and points along the negative x axis. The y vector com

Flauer [41]

Answer:

(a) Magnitude of Vector = 207.73 m

(b) Direction = 65.48°

Explanation:

(a)

The formula to find out the magnitude of a resultant vector with the help of its x and y components is given as follows:

$Magnitude\ of\ Vector = \sqrt{d_{x}^{2} + d_{y}^{2}} = \sqrt{(86.2\ m)^{2} + (189\ m)^{2}}\\\\$

Magnitude of Vector = 207.73 m

(b)

For the direction of the vector we have the formula:

$Direction = tan^{-1}(\frac{y}{x})\\\\Direction = tan^{-1}(\frac{189\ m}{86.2\ m})\\\\$

Direction = 65.48°

4 0

3 years ago

A physics professor is pushed up a ramp inclined upward at an angle 33.0Â° above the horizontal as he sits in his desk chair tha

Andru [333]

Answer:

2.51 m/s

Explanation:

Parameters given:

Angle, A = 33°

Mass, m = 90kg

Inclined distance, D = 2m

Force, F = 600N

Initial speed, u = 2.3m/s

From the relationship between work and kinetic energy, we know that:

Work done = change in kinetic energy

W = 0.5m(v² - u²)

We also know that work done is tẹ product of force and distance, hence, net work done will be the sum of the total work done by the force from the students and gravity.

Hence,

W = F*D*cosA - w*D*sinA

w = m*9.8 = weight

=> W = 600*2*cos33 - 90*9.8*2*sin33

W = 45.7J

=> 45.7 = 0.5*m*(v² - u²)

45.7 = 0.5*90*(v² - 2.3²)

45.7 = 45(v² - 5.29)

=> v² - 5.29 = 1.016

v² = 6.306

v = 2.51 m/s

The final velocity is 2.51 m/s

7 0

3 years ago

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What is laplace law???????

cestrela7 [59]

${\texttt{\huge{\red{ANSWER :-}}}}$

<h3>LAPLACE LAW :-</h3>

Laplace's law for the gauge pressure inside a cylindrical membrane is given by

Where

γ => surface tension

r => the radius of the cylinder

Note : there is an inverse relation between the pressure and the radius.

8 0

2 years ago