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Norma-Jean [14]
3 years ago
11

The density of silver metal bar is 10.5 g/cm3 and it occupies a volume space of 0.5l. What is its mass in kilograms (kg).

Chemistry
1 answer:
mojhsa [17]3 years ago
4 0

Density is equal to the ratio of mass to the volume.

The mathematical expression is given as:

Density = \frac{mass}{volume}

Density of silver metal bar=10.5 g/cm^{3}

Convert g/cm^{3} into g/L

1 cm^{3} = 0.001 L

Thus, density  = \frac{10.5}{10^{-3}} g/L

= 10.5\times 10^{3}g/L

Volume = 0.5 L

Put the values,

10.5\times 10^{3}g/L= \frac{mass}{0.5 L}

m= 10.5\times 10^{3}g/L\times 0.5 L

=5.25 \times 10^{3}g

Now, convert gram into kg

1 g = 0.001 kg

Therefore, mass in kg=  \frac{5.25 \times 10^{3}}{10^{-3}}

= 5.25 kg

Thus, mass of silver metal bar in kg=5.25 kg



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1. V= 161

2. V = 37.3

<h3 /><h3>Further explanation  </h3>

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<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature  </em>

\tt \dfrac{V1}{T1}=\dfrac{V2}{T2}

1.

\tt \dfrac{125}{17+273.15~K}=\dfrac{V2}{100+273.15}\\\\V2=160.7\rightarrow 161~cm^3

2.

\tt \dfrac{27.3}{0+273.15`K}=\dfrac{V2}{100+273.15}\\\\V2=37.3~cm^3

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3 years ago
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The 3 particles are protons, neutrons, and electrons?

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Calculate the percent ionization of a 0.15 M benzoic acid solution in pure water and in a solution containing 0.10 M sodium benz
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Answer:

% ionization for benzoic acid = 0.08%

% ionization for sodium benzoate = 2.5%

The percentage ionization differ significantly because benzoic acid is a weak acid while sodium benzoate is a salt of benzoic acid. Their extent of dissociation also differ because they were compared in different solutions

Explanation:

Ka for pure water = 1.0 * 10-⁷

Ka for sodium benzoate = 6.5*10-⁵

1. For benzoic acid (C6H5COOH)

C6H5COOH ==== C6H5COO‐ + H+

0.15M 0 0

0.15-x x x

Ka = [C6H5COO-] [H+] / [C6H5COOH]

Ka = [X] [X] / 0.15 - X

1.0*10-⁷ = [X]² / 0.15 - x

But x is negligible compared to 0.15,

(1.0*10-⁷)*0.15 = x²

Take square root of both sides,

X = 1.22 * 10-⁴

% ionization = ( [H+] / [C6H5COOH] ) * 100

% ionization = (1.22*10-⁷ / 0.15) * 100

% ionization = 0.08%

2. For C6H5COONa

Note: I will not repeat the same procedure of dissociation again since they're basically the same just the difference in ions

Ka for C6H5COONa = 6.5*10-⁵

6.5*10-⁵ = [X]² / (0.10 - X)

Cross-multiply both sides;

(6.5*10-⁵ * 0.10) = X²

Take square root of both side,

X= 2.5*10-³

% ionization = (2.5*10-³ / 0.10) *100

% ionization = 2.5%

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Answer: The concentration of hydrogen ion is 2.5 x 10∧-3.

Explanation:

It is well known that; pH + pOH = 14

∴ pH + 11.40 = 14

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Remember that,

pH = - Log [ H+ ]

2.60 = - log [H+]

To get the  hydrogen ion concentration, we take the anti-log of 2.60.

[H+] = Antilog 2.60 = 2.5 x 10∧-3.

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Protons and neutrons have about the same mass. Electrons are the smallest out of the three, in fact, protons weigh 1,836 times more than an electron.
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