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8090 [49]
3 years ago
14

HELP ME PLS IM DUMB!!!

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

ur not dumb dw

Step-by-step explanation:

a) 5/6x+8

b)-3/4x-2

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Olivia has a $10,000 hospital bill. She wants to pay it off in 6 years. The required monthly payment on her credit card is $220.
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<span>How much more will it cost Olivia if she uses the credit card instead of the personal loan?
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Use the segment addition postulate to write three equations using the diagram below
creativ13 [48]

Answer:

PQ + QR = PR => equation 1

RS + ST = RT => equation 2

PR + RT = PT => equation 3

Step-by-step explanation:

Points P, Q, R, S, and T are collinear therefore, the following equations can be written based on the segment addition postulate:

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RS + ST = RT => equation 2

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More equations can actually be written from the diagram given using the segment addition postulate. Such as:

PQ + QR + RS + ST = PT

8 0
3 years ago
Which of the following functions best describes this graph?
natita [175]
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4 0
3 years ago
FIND THE SOLUTION OF EACH EQUATION IF THE REPLACEMENT SETS ARE
Yuliya22 [10]
<span>1) There are no solutions for this equation in the solution set.

2) The solution set is {5} because 15/5 = 3

3) The solution set is {8} because 31 = 3 (8) + 7 \\ 31 = 24 + 7 \\ 31 = 31

4) The solution set is {20} because 20 - 13 = 7

5) The solution set is {66} because 22 x 3 = 66

6) A = 32 - 9(2) \\ A = 32 - 18\\ A = 14

7) 12 \times \frac{5}{15} - 3 = Y \\\\ 12 \times \frac{1}{3} -3 = Y \\\\ 4 -3 = Y \\ Y =1

8) </span>27 + \frac{5}{16} = G\\\\G = \frac{432 + 5}{16}\\\\G = \frac{437}{16}\\\\G = 27 \frac{5}{16}

9) R = \frac{9(6)}{ ( 8 + 1 ) 3}\\\\R = \frac{54}{9(3)} \\\\R = \frac{54}{27}\\\\ R = 2

10) 15,579 + 6,220 + 18,995 = G\\\\ G = 40,794
<span>
11) The solution set is {6, 7} because:
 6 -2 < 6, which is 4 < 6
AND
7 - 2 < 6, which is 5 < 6

12) </span><span>The solution set is {9, 11} because:
</span>3 ≥ 25/9, which is 3 ≥ <span>2.77777777778
</span>AND
3 ≥ 25/11, which is 3 ≥ 2.2727272727

Hope this helps :D
3 0
3 years ago
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