Question 1
To find centripetal acceleration, use the formula : centripetal acceleration = v^2/r
so answer would be (3.71)^2/42.85=0.32 (2d.p.)
Question 2
Force =ma
a= (9.98)^2/31.77=3.1350
Force= 3.1350 * 56.63 = 177.54 (2 d.p.)
Answer:
Force, F = 622.28 N
Explanation:
It is given that,
Torque, 
Angle between force and displacement, 
Distance, d = 25 cm = 0.25 m
We need to find the force required to produce the torque. Torque produced by an object is given by :
F is force required to produce torque
So, applied force is 622.28 N.
For a white dwarf star<span> to become explosively active, </span>the gap<span> between the dwarf </span>and therefore the<span> companion </span>should<span> be </span>sufficiently little<span> that the white dwarf's </span>force field will<span> pull matter </span>aloof from<span> the surface of the companion. </span>because of<span> the rotation of the </span>positional representation system<span>, the matter flowing through the mass-transfer stream from the companion star forms a </span>flat <span>disk, </span>known as associate degree<span> accretion disk, </span>that<span> orbits </span>round the white dwarf star<span>.</span>
Answer:
It works by testing the ph levels in those areas it is placed in.
Explanation:
Answer: i dont know sorry
Explanation:
