Question

If A = (6i-8j) units, B = (-8i-3j) units, and C = (26i-19j) units, determine a and b

Answer 1

Answer:

Explanation:

given equation

aA + bB + C = 0

Putting the given values

a(6i-8j) +b (-8i-3j) +(26i-19j) = 0

i ( 6a - 8b ) - j ( 8a + 3 b ) = - 26 i + 19 j

comparing the coefficients of i and j

6a - 8b = -26

8a + 3b = -19.

multiplying first equation by 4 and second equation by 3  

24a - 32 b = - 104

24a + 9b = -57

9b + 32b = -57 + 104

41 b = 47

b = 1.41

6 a - 8 x 1.41 = -26

6a = -14.72

a = - 2.45