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Lunna [17]
4 years ago
5

Please help! I especially need help with the second question but help with the first one would be most appreciated!

Physics
1 answer:
lara31 [8.8K]4 years ago
4 0

Answer:

a) Team A will win.

b) The losing team will accelerate towards the middle line with 0.01 m/s^{2}

Explanation:

Given that Team-A pulls with a force , F_{1} = 50N

and Team-B pulls with a force , F_{1} = 45N

∵ F_{1} > F_{2}

The rope will move in the direction of force F_{1}.

∴ Team-A will win.

b) Considering both the teams as one system of total mass , m = 246+253 = 499 kg

Net force on the system , F = F_{1} - F_{2} = 50-45 = 5N

Applying Newtons first law to the system ,

F = ma , where 'a' is the acceleration of the system.

Since , both the teams are connected by the same rope , their acceleration would be the same.

∴ 5 = 499×a

∴ a = 0.01 m/s^{2}

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ExtremeBDS [4]
The answer is b because it’s right
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A block of mass 5 kg slides down an inclined plane that has an angle of 10. If the inclined plane has no friction and the block
Westkost [7]

The kinetic energy of the block  when it reaches the bottom is 39.2 J.

<h3>Kinetic energy of the block at the bottom</h3>

Apply the principle of conservation of energy.

K.E(bottom) = P.E(top)

P.E(top) = mgh

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P.E(top) = 5 x 9.8 x 0.8

P.E(top) = K.E(bottom) = 39.2 J

Learn more about kinetic energy here: brainly.com/question/25959744

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2 years ago
What is the appropriate term for the movement of the orange liquid in the lava lamp animation?
Taya2010 [7]
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3 years ago
A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50
eduard

Answer:

The x-component of the velocity is 16.07 m/s

The y-component of the velocity is 19.15 m/s

Explanation:

Given;

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The x-component of the velocity (horizontal component) is given as;

V_x = Vcos(50^0)\\\\V_x = 25 \ m/s \ \ \times \ \ 0.6428\\\\V_x = 16.07 \ m/s

The y-component of the velocity (vertical component) is given as;

V_y = Vsin(50^0)\\\\V_y = 25 \ m/s \ \ \times \ \ 0.766\\\\V_y = 19.15 \ m/s

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tatuchka [14]

Answer:

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for example assume you are setting in a moving bus and when someone see you from the ground you are in motion but for some who is with you in the bus you are not in motion.

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