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3 years ago

How does the agricultural activity most likely affect the surface water of the area?

Physics

2 answers:

Radda [10]3 years ago

7 0

Answer:

Agriculture has been the cause of significant modification of landscapes throughout the world. Tillage of land changes the infiltration and runoff characteristics of the land surface, which affects recharge to ground water, delivery of water and sediment to surface-water bodies, and evapotranspiration.

Explanation:

LUCKY_DIMON [66]3 years ago

3 0

Since people throw away things like trash and some oil and other polluting stuff it polluts the ocean

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Thick rubber gloves prevent electric shock because

Kaylis [27]

Answer:

Rubber is an insulator.

Explanation:

Rubber is an insulator. Electricity will always travel "the path of least resistance." Rubber has a very high resistance, so electricity will go somewhere else to find ground.

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3 years ago

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A 3.0 \Omega Ω resistor is connected in parallel to a 6.0 \Omega Ω resistor, and the combination is connected in series with a 4

GarryVolchara [31]

Answer:

The power dissipated in the 3 Ω resistor is P= 5.3watts.

Explanation:

After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.

The resultating resistor is of Req=6Ω.

I= V/Req

I= 2A

the parallel resistors have a potential drop of Vparallel=4 volts.

I(3Ω) = Vparallel/R(3Ω)

I(3Ω)= 1.33A

P= I(3Ω)² * R(3Ω)

P= 5.3 Watts

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4 years ago

Why does air blow out of your lungs when you exhale

Levart [38]

When breathing out, it pushes your diaphragm, the muscle below your lungs, up, which then causes the air to leave your lungs.

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3 years ago

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if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?

LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

The complete question is written below:

In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of $1.80 m/s^{2}$ , it would go from rest to its top speed in 85.6 s.

a) What was the speed of the vessel?

b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute?

Calculate the answers in both meters per second and kilometers per hour

a) The average acceleration $a_{av}$ is expressed as:

$a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t}$ (1)

Where:

$a_{av}=1.80 m/s^{2}$

$\Delta V$ is the variation of velocity in a given time $\Delta t$ , which is the difference between the final velocity $V$ and the initial velocity $V_{o}=0$ (because it starts from rest).

$\Delta t=85.6 s$

Isolating $V$ from (1):

$V=a_{av}\Delta t + V_{o}$ (2)

$V=(1.80 m/s^{2})(85.6 s) + 0 m/s$ (3)

$V=154.08 \frac{m}{s}$ (4)

If $1 km=1000m$ and $1 h=3600 s$ then:

$V=154.08 \frac{m}{s}=554.68 \frac{km}{h}$ (4)

b) Now we need to find the final velocity when $\Delta t=1 min=60 s$ :

$V=(1.80 m/s^{2})(60 s) + 0 m/s$ (5)

$V=108 \frac{m}{s}=388.8 \frac{km}{h}$ (6)

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3 years ago

A 750-kg automobile is moving at 26.2 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car

Kisachek [45]

To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore

Potential Energy can be defined as,

$PE = mgh$