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fiasKO [112]
3 years ago
7

Functions Help please

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

Where are the functions?

Step-by-step explanation:

IRISSAK [1]3 years ago
5 0

A function is a process or a relation that associates each element x of a set X, the domain of the function, to a single element y of another set Y (possibly the same set), the co domain of the function.

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Guysss plsss HEELPPP ME ILL MARK BRAINLIEST PLLLSSSSSS HELP
Vitek1552 [10]

Answer:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

This agrees with the last option in the list of possible answers

Step-by-step explanation:

Recall that the maximum of a parabola resides at its vertex. So let's find the x and y position of that vertex, by using first the fact that the x value of the vertex of a parabola of general form:

y=ax^2+bx+c

is given by:

x_{vertex}=\frac{-b}{2\,a}

In our case, the quadratic expression that generates the parabola is:

y=-2x^2+24x+174

then the x-position of its vertex is:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{-24}{2\,(-2)}\\x_{vertex}=\frac{-24}{-4)}\\x_{vertex}=6

This is the price of the video game that produces the maximum profit (x = $6). Now let's find the y-position of the vertex using the actual equation for this value of x:

y=-2x^2+24x+174\\y_{vertex}=-2\,(6)^2+24\,(6)+174\\y_{vertex}=-72+144+174\\y_{vertex}=246

This value is the highest weekly profit (y = $246).

Now, recall that we can write the equation of the parabola in what is called "vertex form" using the actual values of the vertex position (x_{vertex},y_{vertex}):

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-246=-2\,(x-6)^2\\y=-2\,(x-6)^2+246

Therefore the answer is:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

6 0
3 years ago
Ashley and Kris are saving money for a vacation. Ashley currently has
USPshnik [31]

Answer:

Step-by-step explanation:

1) y = 50x + 2500

2) y = 200x + 1000

if we build a system with the two equations, we have:

50x+2500 = 200x + 1000

150x = 1500

x = 10

y = 2000 + 1000 = 3000

3) 10

4) $3000

8 0
3 years ago
Find the value of p p^2x^2-12x+p+7 one of the zero is 3/2
wel

Answer:

  p = 2  or  p = -2 4/9

Step-by-step explanation:

We can substitute x=3/2 into the equation and solve for the values of p that make the result be zero.

  p^2(3/2)^2 -12(3/2) +p +7 = 0

  9/4p^2 -18 + p + 7 = 0 . . . . eliminate parentheses

  9p^2 +4p -44 = 0 . . . . . . simplify and multiply by 4

  (9p +22)(p -2) = 0 . . . . . factor

Values of p that make 3/2 be one of the zeros are ...

  p = -22/9, p = 2

_____

<em>Additional comment</em>

The <em>zero product rule</em> tells you a product will be zero if and only if a factor is zero. Hence the solutions to the quadratic are values of p that make the factors zero.

  9p +22 = 0   ⇒   9p = -22   ⇒   p = -22/9

  p -2 = 0   ⇒   p = 2

__

For p=2, the solution 3/2 has multiplicity 2. For p=-22/9, the other zero is x=123/242.

8 0
3 years ago
Hi bobs spam and make a huge convo on this app
ipn [44]

Answer:

no this is for actual question for students not for memes bro

7 0
3 years ago
3<br>Which is an asymptote of the graph of the function Y = tan(3/4x)​
azamat

Answer:

2)x=-2π/3

Step-by-step explanation:

The following options are missing:

<em>1)x=-4π/3 </em>

<em>2)x=-2π/3 </em>

<em>3)x=3π/4 </em>

<em>4)x=3π/2</em>

<em />

The trigonometric function tan(x) has asymptotes at x = π/2 radian and x = -π/2 radian. Therefore, tan(3/4x) would have asymptotes at:

3/4x = π/2

x = π/2*4/3

x = 2π/3

or

3/4x = -π/2

x = -π/2*4/3

x = -2π/3

4 0
3 years ago
Read 2 more answers
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