Answer:
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The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
Step-by-step explanation:
Slope = 0
y-y1=m(x-x1)
y-3=0
y = 3
By the Fundamental Theorem of Arithmetic, all number can be expressed as a product of prime numbers.
So naturally, lets divide 120 by an easy prime number.
We know that 120 is even, so lets try 2
120/2 = 60
lets keep dividing it by two until it becomes odd or prime
60/2 = 30
30/2 = 15
now lets see, what are some factors of 15?
Well the obvious ones are 3 and 5, both of which are prime. So now we can just count up how many times we divided it by 2
120/2 = 60
60/2 = 30
30/2 = 15
and 15 is just 3 x 5, so:
<span>
120=(<span>23</span>)×(3)×(5)</span>
or
<span><span>
120 = 2 × 2 × 2 × 3 × 5</span></span>
