s=600 m
t=12 s
s=0.5*a*t² (initial speed V0=0)
a=(2*s)/t²
a=(2*600)/12²
a≈8.33 m/s²
L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)
L=0.5*a*(t2²-t1²)
L=0.5*((2*s)/t²)*(t2²-t1²)
L=0.5*((2*600)/12²)*(12²-11²)
L ≈ 95.83 m
Answer:
The ratio of a distance through which any part of a machine moves to that which driving part moves during the same time.
To calculate the length of the wire, we use formulas,
(A)
(B)
Here, R is the resistance of the wire, I is the current flows through wire and V is potential difference. A is cross sectional area of wire and
is the density of copper wire and is value,
.
Given 
Substituting the values of I and V in equation (A ) we get,

Now from equation (B),

Therefore,

Thus the length of the copper wire is 177.9 m.
The answer to your question is True