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Anna007 [38]
3 years ago
9

How does the molecular structure of a material influence its physical properties?

Physics
1 answer:
kvv77 [185]3 years ago
7 0

All of these properties are due to the chemical structure of the compound. The chemical structure includes the bonding angle, the type of bonds, the size of the molecule, and the interactions between molecules. Slight changes in the chemical structure can drastically affect the properties of the compound.
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Answer: A~ It's very far away

Explanation:

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4 years ago
1. A plane starts from rest and aceelerates in a
larisa86 [58]

s=600 m

t=12 s

s=0.5*a*t² (initial speed V0=0)

a=(2*s)/t²

a=(2*600)/12²

a≈8.33 m/s²

L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)

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3 years ago
Ratio of velocity ratio​
Zolol [24]

Answer:

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4 0
3 years ago
A current of 0.86 a flows through a copper wire 0.47 mm in diameter when it is connected to a potential difference of 15 v. how
likoan [24]

To calculate the length of the wire, we use formulas,

R = \frac{V}{I}                                       (A)

R= \rho  \frac{l}{A}                                (B)

Here, R is the resistance of the wire, I is the current flows through wire and V is potential difference. A is cross sectional area of wire and \rho is the density of copper wire and is value,\rho = 1.7\times 10^{-8} \Omega m.

Given    I = 0.86 A,V=15 V and  r = \frac{0.47 mm}{2} =2.35 \times 10^{-4} m, V= 15 V.

Substituting the values of I and V in equation (A ) we get,

R=\frac{15V}{0.86A} = 17.44 \Omega

Now from equation (B),

l=\frac{R A}{\rho }

Therefore,

l= \frac{17.44\times\pi \times r^2  }{1.7\times 10^{8} \Omega m} \\\\ l= \frac{17.44\times 3.14 \times(2.35\times10^{-4}m)^2  }{1.7\times 10^{-8} \Omega m} = 177.9 m

Thus the length of the copper wire is 177.9 m.

8 0
3 years ago
A deductive argument is always a stronger argument than an inductive argument
statuscvo [17]
The answer to your question is True
8 0
4 years ago
Read 2 more answers
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