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2 years ago

Zoe finds that the temperature of a substance is 12 degrees Celsius. What does this tell Zoe about the substance?

Physics

2 answers:

Vladimir [108]2 years ago

6 0

Answer:

the answer is b

Explanation:

Its average kinetic energy is 12 on the Celsius scale.

maks197457 [2]2 years ago

5 0

Given the temperature, we can tell if the substance is cold or not relative to the reference temperature. For example, compared to the substance having a temperature of 15 degrees C, the substance is colder and it is hotter from the substance of temperature lesser than 12 degrees C.

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A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 17.3 m/s directly upward.

elena-s [515]

Answer:

h=15.27m

Explanation:

Since at maximum height the vertical velocity must be null it's better to use the formula:

$v_f^2=v_i^2+2ad$

We will use this formula for the vertical direction, choosing the upward direction as the positive one, so we have:

$0=v_i^2+2ah$

$h=-\frac{v_i^2}{2a}$

which for our values is:

$h=-\frac{(17.3m/s)^2}{2(-9.8m/s^2)}=15.27m$

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3 years ago

True or false?

blsea [12.9K]

Answer:

True

Explanation:

7 0

2 years ago

Read 2 more answers

Which of the following is the closest to the scientific fact

Finger [1]

B - A theory seems to be the closest

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2 years ago

When an object experiences uniform circular motion the direction of the net force is?

guajiro [1.7K]

In an uniform circular motion, the direction of the net force on the object is radially inward, passing through the center of the circle.

3 0

2 years ago

A satellite that goes around the earth once every 24 hours (86,400 s) is called a geosynchronous satellite. If a geosynchronous

Olegator [25]

Answer:

42244138.951 m

Explanation:

G = Gravitational constant = 6.667 × 10⁻¹¹ m³/kgs²

r = Radius of orbit from center of earth

M = Mass of Earth = 5.98 × 10²⁴ kg

m = Mass of Satellite

The satellite revolves around the Earth at a constant speed

Speed = Distance / Time

The distance is the perimeter of the orbit

$v=\frac{2\pi \times r}{24\times 3600}$

The Centripetal force of the satellite is balanced by the universal gravitational force

$m\frac{v^2}{r}=\frac{GMm}{r^2}\\\Rightarrow \frac{\left(\frac{2\pi \times r}{24\times 3600}\right)^2}{r}=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{r^2}\\\Rightarrow \left(\frac{2\pi \times r}{24\times 3600}\right)^2=6.667\times 10^{-11}\times 5.98\times 10^{24}\\\Rightarrow r^3=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\\\Rightarrow r=\left(\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42244138.951\ m$

The radius as measured from the center of the Earth) of the orbit of a geosynchronous satellite that circles the earth is 42244138.951 m

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2 years ago