Question

g To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 400 loop-per-meter circular coil 0.660 m in radius to create a 1.20 T field (typical of an MRI instrument) at its center with no iron insert.

Answer 1

Answer:

The current inside the MRI solenoid is 2387 A.

Explanation:

Given;

number of turns, N = 400

radius of the loop, r = 0.66 m

magnetic field, B = 1.2 T

The magnetic field strength inside MRI Solenoid is given by;

B = Nμ₀I

Where;

I is the current needed in the loop

$B= N\mu_o I\\\\I = \frac{B}{N \mu_o} \\\\I = \frac{1.2}{(400)(4\pi* 10 ^{-7})} \\\\I = 2387 \ A$

Therefore, the current inside the MRI solenoid is 2387 A.