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RideAnS [48]
3 years ago
7

A 2-kg block slides along a rough horizontal surface and slows to 10 m/s after traveling 20 m. If the kinetic coefficient of fri

ction between the block and surface is 0.2, the initial speed (m/s) of the block was most nearly:
Physics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

initial speed is 13.36 m/s

Explanation:

given data

mass = 2 kg

velocity = 10 m/s

distance = 20 m

friction= 0.2

to find out

initial speed

solution

we find first friction force that is

friction force = friction ×mass×g    ...........1

put here value

friction force = 0.2 × 2 × 9.81  

friction force = 3.924 N

here a will be -ve due to friction

- friction force = mass × acceleration

acceleration = - friction force / mass

acceleration = - 3.924 / 2  

acceleration = - 1.962 m/s²

and we know velocity formula that is  

V² = V(i)² + 2as

put here value

10² = V(i)² + 2(-1.962)(20)

V(i) = 13.36  

so initial speed is 13.36 m/s

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The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t
Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts      

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, \dfrac{N_s}{N_p}=\dfrac{46}{1}

Voltage of primary coil, V_p=120\ V

Current in the secondary coil, I_s=1.8\times 10^{-3}\ A

The power consumed by the air filter is :

P_s=I_s\times V_s...........(1)

For a transformer, \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}

So, P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p

P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120

P_s=9.936\ Watts

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.                

3 0
3 years ago
Read 2 more answers
A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad
sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

           \theta = \frac{S}{r}

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                \theta = \frac{S}{r}

                             = \frac{4}{2}

                             = 2 radians (\frac{180^{o}}{\pi})

                             = 114.64^{o}

Now, we will calculate the charge density as follows.

                 \lambda = \frac{Q}{L}

                            = \frac{18 \times 10^{-9} C}{4 m}

                            = 4.5 \times 10^{-9} C/m

Now, at the center of arc we will calculate the electric field as follows.

                 E = \frac{2k \lambda Sin (\frac{\theta}{2})}{r}

                     = \frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0
3 years ago
This is a small rocky body that orbits the sun, and when close to the sun exhibit a small tail of ice and gas.
Over [174]
This is a comet. It is also called a dirty snowballs.
3 0
3 years ago
When a beam of charged particles moves through a magnetic field, what is the evidence that particles in the beam have momentum g
Vsevolod [243]

The charged particles are often deflated in a magnetic field.

<h3>What is a magnetic field?</h3>

The term charge refers to a positive or negative entity. The can be created when a charge is made to pass through a conductor in a magnetic field.

A magnetic field is created when we have a north pole and a south pole. The charged particles could be made to pass through the electric field and when that happens, we can see a pattern a shown in the image attached.

Thus, we can see that the charged particles are often deflated in a magnetic field.

Learn more about magnetic field:brainly.com/question/23096032

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4 0
1 year ago
Science Seminar Question: Why did Vehicle 2 fall off the cliff in Claire's test of the collision scene but Vehicle 2 did not fal
asambeis [7]

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because, Weight_{vehicle 1} < Weight_{vehicle 2} but in Claire's test, vehicle 2 off the cliff because Weight_{vehicle 1} \geq Weight_{vehicle 2}

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff.  In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.

8 0
3 years ago
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