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RideAnS [48]
3 years ago
7

A 2-kg block slides along a rough horizontal surface and slows to 10 m/s after traveling 20 m. If the kinetic coefficient of fri

ction between the block and surface is 0.2, the initial speed (m/s) of the block was most nearly:
Physics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

initial speed is 13.36 m/s

Explanation:

given data

mass = 2 kg

velocity = 10 m/s

distance = 20 m

friction= 0.2

to find out

initial speed

solution

we find first friction force that is

friction force = friction ×mass×g    ...........1

put here value

friction force = 0.2 × 2 × 9.81  

friction force = 3.924 N

here a will be -ve due to friction

- friction force = mass × acceleration

acceleration = - friction force / mass

acceleration = - 3.924 / 2  

acceleration = - 1.962 m/s²

and we know velocity formula that is  

V² = V(i)² + 2as

put here value

10² = V(i)² + 2(-1.962)(20)

V(i) = 13.36  

so initial speed is 13.36 m/s

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kogti [31]

Answer:

972

Explanation:

6^5/2^3

=7776/8

=972

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3 years ago
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What is the tangent function used to find and what are its units
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3 years ago
If a girl carries groceries up a flight of stairs, is she doing work on the groceries? Explain.​
nikdorinn [45]

Answer:

Explanation:

Yes she is doing work. With or without the groceries, she is still doing work. She does more work with the groceries than without because Work is defined by F which is defined by mass. The mass increases with the groceries.

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4 0
3 years ago
a 2,000 pound car is driving at 60 miles/hour along a straight, level road. what is the net force acting on the car?
SVETLANKA909090 [29]

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5 0
3 years ago
Dua titik yang bermuatan listrik yang sama, mula-mula berjarak 5 cm dan saling tarik menarik dengan gaya 225 N. Agar kedua titik
Serggg [28]

Answer:

15 cm

Explanation:

Dari pertanyaan yang diberikan di atas, diperoleh data sebagai berikut:

Gaya 1 (F₁) = 225 N

Jarak terpisah 1 (d) = 5 cm

Gaya 2 (F₂) = 25 N

Jarak terpisah 2 (d₂) =?

Kita dapat memperoleh persamaan yang berkaitan dengan gaya dan jarak muatan dua titik dengan menggunakan rumus berikut:

F = Kq₁q₂ / d²

Perbanyak silang

Fd² = Kq₁q₂

Menjaga Kq₁q₂ konstan, kita memiliki:

F₁d₁² = F₂d₂²

Dengan rumus di atas maka diperoleh jarak sebagai berikut:

Gaya 1 (F₁) = 225 N

Jarak terpisah 1 (d) = 5 cm

Gaya 2 (F₂) = 25 N

Jarak terpisah 2 (d₂) =?

F₁d₁² = F₂d₂²

225 × 5² = 25 × d₂²

225 × 25 = 25 × d₂²

5625 = 25 × d₂²

Bagilah kedua sisinya dengan 25

d₂² = 5625/25

d₂² = 225

Hitung akar kuadrat dari kedua sisi

d₂ = √225

d₂ = 15 cm

Oleh karena itu, muatan dua titik harus berjarak 15 cm untuk memiliki gaya tarik 25 N

4 0
2 years ago
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