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RideAnS [48]
3 years ago
7

A 2-kg block slides along a rough horizontal surface and slows to 10 m/s after traveling 20 m. If the kinetic coefficient of fri

ction between the block and surface is 0.2, the initial speed (m/s) of the block was most nearly:
Physics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

initial speed is 13.36 m/s

Explanation:

given data

mass = 2 kg

velocity = 10 m/s

distance = 20 m

friction= 0.2

to find out

initial speed

solution

we find first friction force that is

friction force = friction ×mass×g    ...........1

put here value

friction force = 0.2 × 2 × 9.81  

friction force = 3.924 N

here a will be -ve due to friction

- friction force = mass × acceleration

acceleration = - friction force / mass

acceleration = - 3.924 / 2  

acceleration = - 1.962 m/s²

and we know velocity formula that is  

V² = V(i)² + 2as

put here value

10² = V(i)² + 2(-1.962)(20)

V(i) = 13.36  

so initial speed is 13.36 m/s

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An object moving at a constant speed of 25 m/s is making a turn with a radius of curvature of 7 m (this is the radius of the "ki
prisoha [69]

Answer:

- 278.34 kg m/s^2

Explanation:

The rate of the change of momentum is the same as the force.

The force that an object feels when moviming in a circular motion is given by:

F = -mrω^2

Where ω is the angular speed and r is the radius of the circumference

Aditionally, the tangential velocity of the body is given as:

v = rω

The question tells us that

v = 25 m/s

r = 7m

mv = 78 kg m/s

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