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Lerok [7]
3 years ago
12

The magnetic field of an electromagnetic wave in a vacuum is Bz =(2.4μT)sin((1.05×107)x−ωt), where x is in m and t is in s. You

may want to review (Pages 889 - 892) . For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Part A What is the wave's wavelength? Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
tatiyna3 years ago
7 0

Answer:

Explanation:

Given

B_z=(2.4\mu T)\sin (1.05\times 10^7x-\omega t)

Em wave is in the form of

B=B_0\sin (kx-\omega t)

where \omega =frequency\ of\ oscillation

k=wave\ constant

B_0=Maximum\ value\ of\ Magnetic\ Field

Wave constant for EM wave k is

k=1.05\times 10^7 m^{-1}

Wavelength of wave \lambda =\frac{2\pi }{k}

\lambda =\frac{2\pi }{1.05\times 10^7}

\lambda =5.98\times 10^{-7} m

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