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LenaWriter [7]
3 years ago
13

When light waves hit ice, most of them bounce off and radiate back into space. Because of this, ice is best described as which k

ind of surface?
A.) reflective

B.) absorbent

C.) dense

D.) rough​
Physics
2 answers:
viktelen [127]3 years ago
8 0
A. Reflective
The light reflects off the ice

Hope this helped
liberstina [14]3 years ago
7 0
A: Reflective. You can tell this because the light waves are bouncing off of the ice, rather than being absorbed. Hope this helps!
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compare your previous result to the present hrf result are there any changes if yes explain your answer​
garri49 [273]

Answer:

<em>I </em><em>don't</em><em> know</em><em> </em><em>what</em><em> </em><em>are </em><em>you </em><em>saying</em><em> </em><em>but </em><em>I </em><em>don't</em><em> </em><em>have </em><em>any</em><em> </em><em>results</em><em> </em>

Explanation:

kai6417

4 0
2 years ago
Each of the following diagrams shows a spaceship somewhere along the way between Earth and the Moon (not to scale); the midpoint
djyliett [7]

Answer:

F_5 >F_4>F_1 >F_2>F_3

Where F_i represent the force for each of the 5 cases i -1,2,3,4,5 presented on the figure attached.

Explanation:

For this case the figure attached shows the illustration for the problem

We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.

Th formula is given by:

F = G \frac{m_{Earth} m_{Spaceship}}{r^2}

Where G is a constant G = 6.674 x10^{-11} m^2/ (ks s^2)

m_{Earth} represent the mass for the earth

m_{spaceship} represent the mass for the spaceship

r represent the radius between the earth and the spaceship

For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.

Based on this case we can create the following rank:

F_5 >F_4>F_1 >F_2>F_3

Where F_i represent the force for each of the 5 cases i -1,2,3,4,5 presented on the figure attached.

6 0
2 years ago
As part
umka21 [38]

Answer:

Part a)

a = 3.68 m/s^2

Part b)

a = 11.8 m/s^2

Explanation:

Part a)

For force conditions of two blocks we will have

m_1g - T = m_1 a

T - m_2g = m_2 a

now from above equations we have

(m_1 - m_2) g = (m_1 + m_2) a

a = \frac{m_1 - m_2}{m_1 + m_2} g

now we know that

m_1 = \frac{908}{9.8} = 92.65 kg

m_2 = \frac{412}{9.8} = 42 kg

now from above equation we have

a = \frac{92.65 - 42}{92.65 + 42}(9.8)

a = 3.68 m/s^2

Part b)

When heavier block is removed and F = 908 N is applied at the end of the string then we have

F - mg = ma

908 - 412 = 42 a

a = 11.8 m/s^2

8 0
3 years ago
Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a
Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2     (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0
3 years ago
A person is going to take a trip from town eight to town D to do this they travel 60 KM in .45 hour And then stop in town before
ANEK [815]

Answer:

   v = 72 km / h

Explanation:

The definition of average speed is the distance traveled between the time interval

          v = Δx / Δt

let's find the distance traveled

       x = 60 + 30

       x = 90 km

time spent, all time must be included, travel time and when stopped

       t = 0.45 + 0.15 + 0.5+ 0.15

       t = 1.25 h

we substitute in the initial equation

      v = 90 / 1.25

       v = 72 km / h

in going from one city to the other

4 0
3 years ago
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