Answer is: Kw of pure water at 50.0°C is <span>5.50 × 10-14</span><span>.
pH = 6.630.
pH = -log</span>[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-6.63) = 2.34·10⁻⁷ M.
[H⁺] · [OH⁻] = x.
Kw = ?.<span>
Kw = [H</span>⁺] · [OH⁻]. <span>
Kw = x².
Kw = (</span>2.34·10⁻⁷ M)².
Kw = 5.50·10⁻¹⁴ M².
Kw is ionic product of water.
Answer:
Heated water begins circulating in a fish tank.
Explanation:
Answer:
2 moles of Methane gas will occupy 44.8 L
Explanation:
If one mole of any gas occupies 22.4 L under certain conditions of temperature and pressure, and those conditions are assumed in this question, then we comfortably solve this problem as follows;
1 mole of Methane gas ---------------> 22.4 L
2 moles of Methane gas -------------->?
Cross and multiply, 2 moles of Methane gas = 2 X 22.4 L = 44.8L
Therefore, 2 moles of Methane gas will occupy 44.8 L, if the conditions of temperature and pressure are maintained.
OPTION A IS THE RIGHT SOLUTION.
Answer:
2.222 that is the answer i think might want to ask
Answer: Amount of sodium chloride produced is 25.43 grams.
Explanation:
To calculate the moles:
Given: Mass of sodium = 10 g
Molar mass of sodium = 23g/mol
The balanced equation is:
By Stoichiometry of the reaction,
2 moles of sodium produces 2 moles of sodium chloride
So, 0.4347 moles of sodium will produce =
of sodium chloride.
Molar mass of sodium chloride = 58.5 g/mol
Putting values in equation 1, we get:
Hence, amount of sodium chloride produced is 25.43 grams.
