Moles of Bromine produced = 9 moles
<h3>Further explanation</h3>
Given
9 moles of Chlorine gas
Word equation
Required
Moles of Chlorine produced
Solution
We change the word equation into a chemical equation (with a formula)
Aluminum bromide reacts with chlorine gas to produce Aluminum chloride and bromide gas
2AlBr₃+3Cl₂⇒2AlCl₃+3Br₂
moles Cl₂ = 9
Maybe you mean, <em>how many moles of Bromine can we produce?</em>
From equation, mol ratio Cl₂ : Br₂ = 3 : 3, so mol Br₂=mol Cl₂=9 moles
Answer:
Hi there!
The answer to this question is: True
Atoms make up an element
In order to calculate for the amount of CaCl2 and water used we need to multiply the total amount mixture to the percentage of each component. Since we are given a two component mixture CaCl2-water with 40% CaCl2 by mass, therefore we have 60% water.
Amount of CaCl2 = 0.40*(370.9) =148.36 g of CaCl2
Amount of Water = 0.60*(370.9) = 222.54 g of Water
It would be a synthesis reaction
To know if an equation is balanced you need to check and see how much of each molecule is on either side of the arrow. Right now you have 1-Ca, 2-H, 2-Cl on the left side of the arrow and 1-Ca, 2-Cl, and 2-H on the right side too. Because all the molecules are equal on both sides this means that the equation is balanced. So in front of the CaCl2 there is an assumed coefficient of 1. The answer is 1.
