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sergey [27]
2 years ago
6

Which energy transformation occurs in an exothermic reaction?

Chemistry
1 answer:
ivann1987 [24]2 years ago
8 0

Answer:

Energy from the chemical bonds of the reactants is released to the surrounding.

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"Pure acetic acid (HC2H3O2) is a liquid and is known as glacial acetic acid. Calculate the molarity of a solution prepared by di
musickatia [10]

<u>Answer:</u> The molarity of glacial acetic acid is 0.175 M

<u>Explanation:</u>

To calculate the mass of acetic acid, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of acetic acid = 1.05 g/mL

Volume of acetic acid = 5.00 mL

Putting values in above equation, we get:

1.05g/mL=\frac{\text{Mass of acetic acid}}{5.00mL}\\\\\text{Mass of acetic acid}=(1.05g/mL\times 5.00mL)=5.25g

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (acetic acid) = 5.25 g

Molar mass of acetic acid = 60.052 g/mol

Volume of solution = 500.0 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{5.25g\times 1000}{60.052g/mol\times 500.0mL}\\\\\text{Molarity of solution}=0.175M

Hence, the molarity of glacial acetic acid is 0.175 M

5 0
2 years ago
What describes how much of a substance has been dissolved into another substance and is usually expressed in a ratio or percent?
gregori [183]
<h3>Answer: <u><em>It's A Hope this helps </em></u></h3>

<h3>Explanation: </h3><h3><u><em>Well this answer was a bit tricky well A and B were like the same definition and thinking  A  but C and D were both wrong  </em></u></h3><h3><u><em /></u></h3>
7 0
2 years ago
Predict whether a reaction occurs, and write balanced complete and net ionic equations:(a) Iron (III) chloride (aq) + cesium pho
Neporo4naja [7]

Answer : The balanced complete and net ionic equations are written below.

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The balanced molecular equation will be,

FeCl_3(aq)+Cs_3PO_4(aq)\rightarrow 3CsCl(aq)+FePO_4(s)

The complete ionic equation in separated aqueous solution will be,

Fe^{3+}(aq)+3Cl^{-}(aq)+3Cs^{+}(aq)+PO_4^{3-}(aq)\rightarrow 3Cs^{+}(aq)+3Cl^{-}(aq)+FePO_4(s)

In this equation the species present are, 3Cl^{-}\text{ and }Cs^{+} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Fe^{3+}(aq)+PO_4^{3-}(aq)\rightarrow FePO_4(s)

(b) The balanced molecular equation will be,

2NaOH(aq)+Cd(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Cd(OH)_2(s)

The complete ionic equation in separated aqueous solution will be,

2Na^{+}(aq)+2OH^{-}(aq)+Cd^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+Cd(OH)_2(s)

In this equation the species present are, Na^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Cd^{2+}(aq)+2OH^{-}(aq)\rightarrow Cd(OH)_2(s)

(c) The balanced molecular equation will be,

MgBr_2(aq)+2CH_3COOK(aq)\rightarrow (CH_3COO)_2Mg(aq)+2KBr(aq)

The complete ionic equation in separated aqueous solution will be,

Mg^{2+}(aq)+2Br^{-}(aq)+2K^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Mg^{2+}(aq)+2CH_3COO^{-}(aq)+2Br^{-}(aq)+2K^{+}(aq)

In this equation all the species are the spectator ions.

Thus, there is no net ionic equation.

(d) The balanced molecular equation will be,

Ag_2SO_4(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+BaSO_4(s)

The complete ionic equation in separated aqueous solution will be,

2Ag^{+}(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2AgCl(s)+BaSO_4(s)

In this equation no species are the spectator ions.

Thus, there is no net ionic equation.

(e) The balanced molecular equation will be,

Na_2SO_4(aq)+Sr(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+SrSO_4(s)

The complete ionic equation in separated aqueous solution will be,

2Na^{+}(aq)+SO_4^{2-}(aq)+Sr^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+SrSO_4(s)

In this equation the species present are, Na^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Sr^{2+}(aq)+SO_4^{2-}(aq)\rightarrow SrSO_4(s)

5 0
3 years ago
How do you label the delta E, on an energy diagram
vladimir1956 [14]
Delta energy on labelled diagram is attached below

4 0
3 years ago
How many moles of aluminum are in 4.35 moles of al2si4o10(OH)2
Gnoma [55]

Answer:

8.7 mol Al

Explanation:

You have the compound Al₂Si₄O₁₀(OH)₂.  Within the compound, you have atoms.  You can tell how many atoms there are by looking at the subscript.  You have 2 aluminum atoms, giving you 8.7 moles of aluminum.

4.35 × 2 = 8.7

6 0
3 years ago
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