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3 years ago

Koi hai kya yha par...??

Chemistry

1 answer:

Delicious77 [7]3 years ago

6 0

Answer:

yesss

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Guys please answer this

iren [92.7K]

Answer:

Mass = 96 g

Explanation:

Given data:

Number of moles of C = 8 mol

Mass of C in gram = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of C = 12 g/mol

8 mol = mass / 12 g/mol

Mass = 8 mol × 12 g/mol

Mass = 96 g

6 0

3 years ago

The concentration of HCl can be determined by titration with a primary standard such as Na2CO3 (sodium carbonate). The titration

Masteriza [31]

Answer:

The concentration of HCl is 0.275 M

Explanation:

Step 1: Data given

Mass of Na2CO3 = 0.521 grams

Molar mass of Na2CO3 = 105.99 g/mol

Volume of HCl = 35.7 mL

Step 2: The balanced equation:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

CO3(2-) + 2H+ ---> H2O + CO2

Step 3: Calculate moles of Na2CO3

Moles Na2CO3 = mass Na2CO3 / Molar mass Na2CO3

Moles Na2CO3 = 0.521 grams / 105.99 g/mol

Moles Na2CO3 = 0.0049 moles

Step 4: Calculate moles of HCl

For 1 mol of Na2CO3 consumed, we need 2 moles of HCl

moles of HCL = 2 * 0.0049 = 0.0098 moles HCl

Step 5: Calculate molarity of HCl

Molarity = number of moles of HCl / Volume (liters)

Molarity = 0.0098 moles / 0.0357 L

Molarity = 0.275 M

The concentration of HCl is 0.275 M

4 0

3 years ago

Read 2 more answers

A chemist has 2.0 mol of methanol (CH3OH). Molar mass of menthanol is 32.0g/mol. What is the mass, in grams, of the sample

Mademuasel [1]

2.0 mol x 32.0 g / 1 mol =

3 0

3 years ago

Question: What is the molar concentration of 1.29 mol of KCL dissolved in 350 mL of solution?

STatiana [176]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

$M=\frac{1.29mol}{0.350L}\\\\M=3.69M$

Which gives molar units, M, or just mol/L.

Regards!

8 0

3 years ago

What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?

Anvisha [2.4K]

Answer:

= C3H4N

Explanation:

We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

We first calculate the number of moles of each element.

Carbon = 90g/12 g/mol

= 7.5 moles

Hydrogen = 11 g/ 1 g/mol

= 11 moles

Nitrogen = 35 g/ 14 g/mol

= 2.5 moles

The we get the mole ratio of the elements;

= 7.5/2.5 : 11/2.5 : 2.5 /2.5

= 3 : 4.4 : 1

= 3 : 4 : 1

Therefore;

The empirical formula will be; C3H4N

6 0

3 years ago

Koi hai kya yha par...??​

Koi hai kya yha par...??