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Trava [24]
3 years ago
15

A student experimentally determines the density of a metal cube. The edge length of the cube is measured using calipers. The cub

e's true density is 12.30 g/cm. Use the student's collected data below and calculate the percent error for the measurement.
Student's Collected Data:
Cube's Mass 551786
Edge Length 1.72 cm
Percent error= _______%
Chemistry
1 answer:
IgorC [24]3 years ago
8 0

Answer:

10.9%.

Explanation:

The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;

The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.

The next thing you do is to Determine the exponential density, the can be done by using the formula below;

The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.

Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.

Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.

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The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon
tigry1 [53]

Answer:

\boxed{\text{300 g}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:         32                          60

           CH₃OH + CO ⟶ CH₃COOH

m/g:        160

(a) Moles of CH₃OH

\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}

(b) Moles of CH₃COOH

\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}

(c) Mass of CH₃COOH

\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}

3 0
4 years ago
The body gets rid of lactic acid in a chemical pathway that requires ___________. A. carbon dioxide . B. oxygen . C. amino acids
Luden [163]
The body gets rid of acid in a chemical pathway that requires oxygen. The correct answer is B, oxygen. 
5 0
3 years ago
I need help with this one
Kruka [31]

Answer:

H, B, G, D, E, C, A, F

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7 0
3 years ago
What is the final concentration if a 50.0 mL sample of a 15% H2SO4 solution is added to water to give a final volume of 250 mL?
Anna007 [38]

Answer:

The answer to your question is 3% H2SO4 solution

Explanation:

Data

Concentration 2 = C₂ = ?

Concentration 1 = C₁ = 15 %

Volume 1 = V₁ = 50 ml

Volume 2 = V₂ = 250 ml

Formula

             C₁V₁  = C₂V₂

Solve for C₂

             C₂ = C₁V₁ / V₂

Substitution

             C₂ = (15)(50) / 250

Simplification and result

             C₂  = 3 %

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Answer:

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Explanation:

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