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Trava [24]
3 years ago
15

A student experimentally determines the density of a metal cube. The edge length of the cube is measured using calipers. The cub

e's true density is 12.30 g/cm. Use the student's collected data below and calculate the percent error for the measurement.
Student's Collected Data:
Cube's Mass 551786
Edge Length 1.72 cm
Percent error= _______%
Chemistry
1 answer:
IgorC [24]3 years ago
8 0

Answer:

10.9%.

Explanation:

The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;

The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.

The next thing you do is to Determine the exponential density, the can be done by using the formula below;

The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.

Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.

Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.

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Mrrafil [7]
In physics, power is the rate of doing work. It is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. In the SI system, the unit of power is the joule per second (J/s), known as the watt in honour of James Watt, the eighteenth-century developer of the steam engine.
6 0
3 years ago
1. Metallic strontium crystallizes in a face-centered cubic lattice, with one Sr atom per lattice point. If the edge length of t
Zarrin [17]

Answer:

r=215pm

N_{Mn}=20

Explanation:

From the question we are told that:

Edge length of the unit cell l=608pm

a)

Generally the equation for The relationship between edge length and radius is mathematically given by

4r=\sqrt{2a}

Therefore

4r=\sqrt{2*608}

r=\frac{\sqrt{2*608}}{4}

r=215pm

b)

From the question we are told that:

Density \rho=7.297

Edge length of l=630.0 pm=>630*10^-{10}

Therefore Volume  is given as

V=l^3

V=630*10^-{10}^3

V=2.50047*10^{−22}

Generally the equation for Mass is mathematically given by

m=Volume*density

m=V*\rho

m=2.50047*10^{−22}*7.297

m=1.83*10^{-21}g

Therefore Molarity is given as

n=\frac{M}{Molar M}

n=\frac{1.83*10^{-21}g}{55}

n=3.32*10^{-23}

Finally The atoms in a unit cell is

N_{Mn}=Moles*Avogadro\ constant

N_{Mn}=3.32*10^{-23}*6.023*10^{23}

N_{Mn}=20

7 0
3 years ago
which molecules show an appropriate number of bonds around each carbon atom? select the three that apply.
iren2701 [21]

The appropriate number of bonds around each carbon atom are four covalent bonds

Please note that carbon has four valence electrons in its outermost shell

<h3>What is an element?</h3>

An element is a substance which cannot be split into simpler forms by an ordinary chemical process. This simply goes to say that elements are substances which cannot be decomposed into simpler substances by ordinary chemical reactions.

An atom is the smallest unit or part of an element which can take part in a chemical reaction.

On a general note, elements are classified as thus:

  • Metals, non-metal, and metalloid.

  • The extreme left side elements in the periodic table are metals, for example, aluminum, sodium, calcium, caesium, etc.

  • However, elements on the right side are generally referred to as non-metals, carbon, chlorine, oxygen,

So therefore, the appropriate number of bonds around each carbon atom are four covalent bonds

Complete question:

What is the appropriate number of bonds around each carbon atom?

Learn more about atoms and elements:

brainly.com/question/6258301

#SPJ1

5 0
2 years ago
Does anyone know the answer???​
Fofino [41]
Yes the correct answer is 3.14
5 0
3 years ago
Read 2 more answers
Unit 1- Unit Assessment (Matter &amp; Density)
konstantin123 [22]

Answer:

<h3>The answer is 11 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 3025 g

volume = 275 mL

We have

density =  \frac{3025}{275}  \\

We have the final answer as

<h3>11 g/mL</h3>

Hope this helps you

7 0
3 years ago
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