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Trava [24]
2 years ago
15

A student experimentally determines the density of a metal cube. The edge length of the cube is measured using calipers. The cub

e's true density is 12.30 g/cm. Use the student's collected data below and calculate the percent error for the measurement.
Student's Collected Data:
Cube's Mass 551786
Edge Length 1.72 cm
Percent error= _______%
Chemistry
1 answer:
IgorC [24]2 years ago
8 0

Answer:

10.9%.

Explanation:

The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;

The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.

The next thing you do is to Determine the exponential density, the can be done by using the formula below;

The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.

Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.

Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.

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Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {
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Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH<span>+, and OH-</span>?

b) Calculate <span>Kb</span> for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.<span>
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3 years ago
How many molecules of carbon dioxide are dissolved in 0.550 L of water at 25 °C if the pressure of CO2 above the water is 0.250
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<u>Answer:</u> The number of molecules of carbon dioxide gas are 2.815\times 10^{21}

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.034mol/L.atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = pressure of carbon dioxide gas = 0.250 atm

Putting values in above equation, we get:

C_{CO_2}=0.034mol/L.atm\times 0.250atm\\\\C_{CO_2}=8.5\times 10^{-3}M

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of carbon dioxide = 8.5\times 10^{-5}M

Volume of solution = 0.550 L

Putting values in above equation, we get:

8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 4.675\times 10^{-3} moles of carbon dioxide will contain = (6.022\times 10^{23}\times 4.675\times 10^{-3})=2.815\times 10^{21} number of molecules

Hence, the number of molecules of carbon dioxide gas are 2.815\times 10^{21}

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