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Vitek1552 [10]
3 years ago
10

How many carbon atoms are represented in the formula for CaMg3(CO3)4​

Chemistry
1 answer:
Galina-37 [17]3 years ago
3 0
The formula is for 1 Calcium, 3 Magnesium, 4 Carbon, & 12 Oxygen. The 4 after the parenthesis of (CO3) distributes to each element.

Answer : There are 4 Carbon atoms in the formula.
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2] Calculate the percentage of the element forming sugar glucose C6H1206<br>[C=12, H=1, 0=16]​
inysia [295]

Answer:

wouldn't it be 52

Explanation:

3 0
3 years ago
Lists how many valence electrons are shared, gained, or lost by each atom of the 6 compounds?      
Blababa [14]
<span>The number of electrons in an atom's outermost valence shell governs its bonding behavior.

In N</span>₂, three electrons are being shared by each nitrogen atom, making a total of 6 shared electrons.

In CCl₄, 4 electrons are being shared by each carbon atom and 1 electron is being shared by each chlorine atom

In SiO₂, 4 electrons are being shared by each silicon atom and 2 electrons are being shared by each oxygen atom.

In AlCl₃, 3 electrons are being shared by each aluminum atom and 1 electron is being shared by each Cl atom

In CaCl₂, 2 electrons are lost by the calcium atom and 1 electron is gained by each chlorine atom

In LiBr, 1 electron is lost by the lithium atom and 1 electron is gained by the bromine atom
6 0
3 years ago
Warning signs are sometimes placed on aerosol cans to prevent people from throwing them into a fire. What would be true about th
GarryVolchara [31]

Answer:

The correct option is volume stays constant

Explanation:

When a gas container (in this case an aerosol can) is subjected to heat (from fire), the temperature of the can and subsequently <u><em>the temperature of the gas itself increases</em></u>, an increase in the temperature of the gas cause <u><em>the pressure to also increase;</em></u> as the gas molecules will collide more and faster with each other and against the wall of the can. However, the volume of the gas will remain the same as before it was subjected to the heat - the gas particles do not get destroyed or increased as a result of the heat (law of conservation of matter explains this).

3 0
3 years ago
Read 2 more answers
N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
kow [346]

Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

a-x=2.9M

Thus, the final concentration of N_2O_5 is, 2.9 M

3 0
3 years ago
If 16.29 grams of Na2SO4 is mixed with 3.697 grams of C and allowed to react according to the balanced equation: Na2SO4(aq) + 4
abruzzese [7]

<u>Answer:</u> The limiting reagent in the given chemical reaction is carbon metal.

<u>Explanation:</u>

Excess reagent is defined as the reagent which is present in large amount in a chemical reaction.

Limiting reagent is defined as the reagent which is present in small amount in a chemical reaction. Formation of product depends on the limiting reagent.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For sodium sulfate:</u>

Given mass of sodium sulfate = 16.29 g

Molar mass of sodium sulfate = 142 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium sulfate}=\frac{16.29g}{142g/mol}=0.115mol

  • <u>For carbon:</u>

Given mass of carbon = 3.697 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{3.697g}{12g/mol}=0.31mol

For the given chemical reaction:

Na_2SO_4(aq.)+4C(s)\rightarrow Na_2S(s)+4CO(g)

By Stoichiometry of the reaction:

4 moles of carbon reacts with 1 mole of sodium sulfate

So, 0.31 moles of carbon will react with = \frac{1}{4}\times 0.31=0.0775mol of sodium sulfate

As, given amount of sodium sulfate is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon metal is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent in the given chemical reaction is carbon metal.

4 0
3 years ago
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