Answer:
205.3°C
Explanation:
Given parameters:
V₁ = 0.287L
V₂ = 0.18L
T₂ = 37°C
Unknown:
T₁ = ?
Solution:
Since we are interested in volume and temperature relationships in a fixed pressure of the balloon, Charles's law will be a perfect solution to this problem.
Charles's law states that "At constant pressure, the volume of a fixed mass of gas is directly proportional to its temperature".
Mathematically;
where V and T are volume and temperature of the gas
1 and 2 are initial and final states;
let us convert T₂ = 37°C to K; 37 + 273 = 300K
Input the parameters and solve for the unknown;
T₁ = 478.3K
Now convert back to °C; 478.3 - 273 = 205.3°C
Answer: 1075.5 mph
Explanation:anything moving at 4.78*10^4 cm/sec
equivalent to
cm —> miles = 1/1.6*10^5
sec —> hr = 1/3600
[4.78*10^4]*3600/1.6*10^5 = 1075.5 mph
Astatine. Because it has the smaller shell of electrons. I believe
2CuI (s) + I₂ (aq) → 2 Cu⁺² (aq) + 4 I⁻ (aq)
When writing an equilibrium expression, we use the following values:
A (aq) + 3B (aq) → 2C (aq) + 2D (aq)
The numbers were arbitrary molar equivalents and the uppercase letters are the molecules in the reaction. The species used in the equilibrium expression but all be in the same state, e.g., solid, liquid, aqeuous.
Kc = [C]²[D]² / [A][B]³
We write the formula by taking the concentration of the products, each to the power of their molar equivalent, and multiply them together. We then divide the products by the concentration of the reactants, also to the power of their molar equivalent.
Going back to the initial equation given, we can now write a Kc expression.
Kc = [Cu⁺²]²[I⁻]⁴ / [I₂]
It should be noted that the CuI (s) in the reaction was left out of the Kc expression. Pure solids and liquids are left out of the expression and only the aqueous species are included. The reason being that, in this case, solid CuI does not affect the amount of reactant at equilibrium. Therefore, we just leave the concentration for [CuI] = 1, and remove it from the expression.