Anemia is essentially an iron deficiency so the element found in the liver preventing it would be Fe (iron).
Answer:
We need 6.0 moles of aluminium
Explanation:
Step 1: Data given
Number of moles of H2 = 9.0 moles
Step 2: The balanced equation
2 Al + 6 HCl → 2 AlCl3 + 3H2
Step 3: Calculate moles Al
For 2 moles Aluminium, we need 6 moles HCl to produce 2 moles AlCl3 and 3 moles H2
For 9.0 moles of H2 we need 2/3 * 9.0 = 6.0 moles of aluminium
We need 6.0 moles of aluminium
A coal because coal is one of the most natural items on the list
Answer:
Q14: 17,140 g = 17.14 kg.
Q16: 504 J.
Explanation:
<u><em>Q14:</em></u>
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).
m is the mass of the ice (m = ??? g).
c is the specific heat of the ice (c of ice = 2.1 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).
∵ Q = m.c.ΔT
∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)
∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.
<u><em>Q16:</em></u>
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat absorbed by ice (Q = ??? J).
m is the mass of the ice (m = 12.0 g).
c is the specific heat of the ice (c of ice = 2.1 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).
∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.
