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3 years ago

7

The dimension line is connected to the part being measured by _______________. A. Hidden lines B. Extension lines C. Visible lin

es D. Section lines

2 answers:

salantis [7]3 years ago

6 0

Extension lines! its on google!

kondaur [170]3 years ago

3 0

B: Extension Lines! You could have just searched this up on google

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In a chemical equation, the chemicals that react are considered . In a chemical equation, the chemicals that are produced are co

vovangra [49]

Answer

Hi,

In a chemical equation, chemicals that react are the reactants, while chemicals that are produced are the products/by products. Both sides of the equation must be balanced.

Explanation

When writing a chemical equation, reactants reacts to produce products. For example in the equation for formation of water, hydrogen combines with oxygen as 2H₂ +O₂→2H₂O where the first part before the arrow represent the reactants and the next part after the arrow are the products. Reactants are on the left where as products are on the right.Coefficient 2, in this cases is used for balancing the equation.

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3 years ago

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Which of the following objects is accelerating?

jenyasd209 [6]

Answer:

A

Explanation:

Constant speed (without change in direction) is not accelerating. If you are slowing down, speeding up, or changing direction, you are accelerating

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3 years ago

Which of the following is not a part of the SMART acronym? Question 5 options: Specific Measurable Respectable Time-bound

juin [17]

The answer is Respectable

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2 years ago

The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i

Sergio [31]

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius= $r=\frac{d}{2}=\frac{2.3}{2}=1.15 m$

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency= $\frac{1200}{60}=20 Hz$

1 minute=60 seconds

Angular velocity= $\omega=2\pi f$

Angular velocity= $2\times \frac{22}{7}\times 20=125.7 rad/s$

b.We have to find the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac.

$v=r\omega=1.15\times 125.7=144.56 m/s$

c.Centripetal acceleration= $\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2$

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7 0

3 years ago

A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic

Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

$\epsilon=Blv\sin\theta$

Here,

$\theta$ is the angle between magnetic field and the wire’s velocity

$\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}$

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0

3 years ago