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Arte-miy333 [17]

2 years ago

5

What is the answer, friends?

1 answer:

aniked [119]2 years ago

5 0

Your answer is C. hope this helped! :)

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An unknown number of identical light bulbs are connected to a 15 V battery in parallel. The current through the battery is 2 A.

zaharov [31]

Answer:

An unknown number of identical light bulbs are connected to a 15 V battery in parallel. The current through the battery is 2 A. If the light bulbs are connected to the battery in series, the current through the battery is 5 mA. How many bulbs are there?

3 bulbs are there from the analogy given above

Explanation:

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2 years ago

How much work is needed to push a 117- kg packing crate a distance of 2.75 m up an inclined plane that makes an angle of 28 o wi

Nataly_w [17]

Answer:

$W_{tot,min} = 1481.372\,J$

Explanation:

The minimum total work is the work needed to counteract the work associated with the weight:

$W_{tot, min} = W_{F}$

$W_{tot,min} = m\cdot g\cdot \sin \theta \cdot \Delta s$

$W_{tot,min} = (117\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (\sin 28^{\textdegree}) \cdot (2.75\,m)$

$W_{tot,min} = 1481.372\,J$

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3 years ago

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Vladimir [108]

Does this help at all to answer the question

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2 years ago

A series LR circuit contains an emf source of 19 V having no internal resistance, a resistor, a 22 H inductor having no apprecia

masha68 [24]

Answer: R = 394.36ohm

Explanation: In a LR circuit, voltage for a resistor in function of time is given by:

$V(t) = \epsilon. e^{-t.\frac{L}{R} }$

ε is emf

L is indutance of inductor

R is resistance of resistor

After 4s, emf = 0.8*19, so:

$0.8*19 = 19. e^{-4.\frac{22}{R} }$

$0.8 = e^{-\frac{88}{R} }$

$ln(0.8) = ln(e^{-\frac{88}{R} })$

$ln(0.8) = -\frac{88}{R}$

$R = -\frac{88}{ln(0.8)}$

R = 394.36

In this LR circuit, the resistance of the resistor is 394.36ohms.

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3 years ago

What is the difference between habitats and niches?

jeyben [28]

Habitats is a place were someone or something lives, and idk what a ninch is

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3 years ago

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