The description below proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
<h3>How to prove an Isosceles Triangle?</h3>
Let ABC be an isosceles triangle such that AB = AC.
Let AD be the bisector of ∠A.
We want to prove that BD=DC
In △ABD & △ACD
AB = AC(Thus, △ABC is an isosceles triangle)
∠BAD =∠CAD(Because AD is the bisector of ∠A)
AD = AD(Common sides)
By SAS Congruency, we have;
△ABD ≅ △ACD
By corresponding parts of congruent triangles, we can say that; BD=DC
Thus, this proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
Read more about Isosceles Triangle at; brainly.com/question/1475130
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Answer:
7.6 inches to make an acute triangle
Step-by-step explanation:
a^2+b^2=c^2
7^2+3^2=c^2
49+9=c^2
58=c^2
Square root both sides
c=7.6 inches
Check the picture below.
∡a has a vertical angle sibling of 40°, and vertical angles are always congruent.
∡b is the 3rd angle in a triangle, the other two are 40° and 90°, recall all interior angles in a triangle add up to 180°.
∡c is a linear angle, namely an angle on the same flat-line as another, and linear angles always add up to 180°.
