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3 years ago

Pls look at the picture and answer

Mathematics

2 answers:

Ratling [72]3 years ago

7 0

Below -2:

-4.5

-2.5

Between -2 and 1:

-0.5

0.5

Above 1:

1.5

On a number line, it'd go like (from left to right): -4.5, -2.5, -0.5, 0.5, 1.5, 4

melisa1 [442]3 years ago

5 0

Answer:

-0.5 goes between -2 and 1

0.5 goes between -2 and 1

-4.5 goes below -2

-2.5 goes below -2

1.5 goes above 1

4 goes above 1

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Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red

lorasvet [3.4K]

Answer:

$P(R_{2}) =\frac{10}{15} = 0.667$

Step-by-step explanation:

Step 1: Understanding the possible events

Selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be completed in two ways:

A. Selecting a red chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

B. Selecting a white chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

Therefore total probability is:

$P(R_{2}) = P(A) + P(B)$

Step 2: Probability of selecting either chip from Urn I

Urn I contains 2 reds and 4 white chips, that gives a total of 6 chips.

$P(R_{1}) = \frac{2}{6} =\frac{1}{3}$

$P(W_{1}) = \frac{4}{6} =\frac{2}{3}$

Step 3: Probability of selecting a red chip from Urn II

Urn II originally contains 3 reds and 1 white chip, that gives a total of 4 chips.

Remember: Once a chip is added from Urn I to Urn II the total number of chips will increase in the Urn II

Case 1: When a red chip is added from Urn I to Urn II

Red chips = 4

White chips = 1

Total Chips = 5

$P(R_{2_1}) = \frac{4}{5}$

Case 2: When a white chip is added from Urn I to Urn II

Red chips = 3

White chips = 2

Total Chips = 5

$P(R_{2_2}) = \frac{3}{5}$

Therefore the total Probability of selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be calculated as:

$P(R_{2}) = P(A) + P(B)$

$P(R_{2}) = P(R_{1}) . P(R_{2_1}) + P(W_{1}) . P(R_{2_2})$

$P(R_{2}) =\frac{1}{3} . \frac{4}{5} + \frac{2}{3} .\frac{3}{5}$

$P(R_{2}) =\frac{4}{15} + \frac{2}{5}$

$P(R_{2}) =\frac{10}{15} = 0.667$

8 0

3 years ago

What is 96-6xsquared

Sidana [21]

Answer:

The Answer = 60

Step-by-step explanation:

Solution:

96 - (6)^2

= 96 - 36

= 60

Therefore,

The Answer = 60

PLEASE MARK ME AS BRAINLIEST

4 0

3 years ago

Oliver read for450 minutes this month. His goal is to read for 10% more minutes next month. If Oliver meets his goal, how many m

Vedmedyk [2.9K]

Answer:

He will have read 495 minutes

Step-by-step explanation:

10 percent of 450 is 45, add that to 450 and you get 495

4 0

4 years ago

Read 2 more answers

If segment ac and segment bc are tangent to circle o find the value of x

Vladimir79 [104]

Answer:

x = 150°

Step-by-step explanation:

Start by cutting the shape into two triangles by bisecting the 30°

Now we have two triangles that have two angles 90° and 15°

Subtract 15° from 90°, you'll get 75°

Double 75° because x is split into 2

150° = x

Also, were given 3 angles, this is a quadrilateral.

90° + 90° + 30° = 210°

360° - 210° = 150°

3 0

4 years ago

Read 2 more answers

Summation notation help!!!!

solniwko [45]

3 is always on the numerator. It is not effected by a power. The answer has to be something that leaves the numerator alone. That means that B is not correct.

The answer is going to be something that makes the denominator 1 when n = 1. That's going to be the answer to the question, because the first term in the sequence is just 3. The denominator must be 1. (not zero).

D is not the answer, because 3/5^1 = 3/5, so D is wrong.

A is not going to get us anywhere either. 3/5^(1 + 1) = 3/5^2 = 3/25 which is not the first term.

The only choice we have left is C. It must be the answer. 3/5^(1 - 1) = 3/5^0 = 3/1 = 3. There's your answer. Note anything raised to the zero power = 1.

4 0

4 years ago