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ExtremeBDS [4]
2 years ago
11

T

Mathematics
1 answer:
ad-work [718]2 years ago
8 0

Answer:

Present age

Son: 15

Father: 45

Step-by-step explanation:

Remark

Thank you for the translation. Without it, the problem would be impossible -- at least for me.

Givens

Let the present age of the father = x

Let the present age of the son = y

Solution

x + y = 60

How many years will pass? You could say it's z.

x + z = y                          When z years pass, the son will be his father's present age.

x + z + y + z = 120          when z is added to both their current ages, the result is 120                   Collect like terms

       

x + y + 2z = 120            

<u>x + y         = 60  </u>            Subtract The very first equation

2z = 60                          Divide by 2

z = 60/2                         30 years have passed.

z = 30

x + z = y

x + 30 = y                       Substitute x + 30 for the present y value (the father).

x + x + 30 = 60

2x = 30

x = 15

x + y = 60

15 + y = 60

y = 60 - 15

y = 45

So the son's age right now is 15

The father's age right now is 45

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