I have more than one so first one is
1 answer:
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Answer:
0.1463
Step-by-step explanation:
Number of observations = 10
Sample mean = 10.5
Sum of standard deviation = 264.5
X = 14
We are to calculate The leverage statistic for study hour 14 using the data above
= 1/10 + (14-10.5)²/264.5
= 1/10 + 3.5²/264.5
= 0.1 +12.25/264.5
= 0.1+0.04631
= 0.1463 is the leverage statistic for the study
Answer:
C. x³+10x²−5x+5
E. 7x⁵+4x²
F. x+8
Step-by-step explanation:
The graph they described should look something like the one i drew below.
So all you have to do is look at the number with the highest exponent.
If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.
x³ is good
-x³ is bad because of the negative sign
x² is bad because exponent is even
x⁷ is good
123x¹ is good
