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Novosadov [1.4K]
3 years ago
5

If a gas has a volume of 2 L at a pressure of 325 kPa, what volume will it have when the pressure is increased to 650 kPa? Assum

e the temperature and number of particles are constant.
Chemistry
1 answer:
Nastasia [14]3 years ago
7 0
P1v1=p2v2
v2=p1v1/p2
v2=325x2/650 = 1 L :)
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Anna007 [38]

Answer:

The false statement is b.

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Explanation:

This excersise refers to colligative properties.

Boiling point refers to the property of boiling point elevation. In a solution of ions, as water sea or water from lakes, the boiling point will be higher than water pure.

It is logical to say that, because these sort of water have ions. Remember that colligative properties depends on the solute particles.

T° boiling solution - T° pure solvent = Kb . m . i

In the freezing point depression, we have the oppossite of boiling point elevation. Freezing point of solution is lower than pure solvent, according to this:

T° freezing pure solvent - T° freezing solution = Kc . m . i

We have to always consider the i, which means Van't Hoff factor, number of ions dissolved in solution. As the i is higher, the freezing point of solution will be lower, and the boiling point of solution will be higher.

They are true statement a and c.

In solution of., [NaCl] = 0.1M, as it is a higher concentration, the molality is also higher than a solution of [NaCl] = 0.05.

As water sample form Salt Lake has certain ions, it is logical to say that the boiling point of this water is higher than boiling point of pure water.

5 0
3 years ago
The equation for the combustion of CH4 (the main component of natural gas) is
Lera25 [3.4K]

Heat produced =  -13588.956 kJ

<h3>Further explanation</h3>

Given

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So Heat produced :

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