3. It has 3 symmetrical lines, so, therefore, has 3 lines of reflectional symmetry.
Hope this helps!
<em>~cupcake </em>
Beth's description of the transformation is incorrect
<h3>Complete question</h3>
Beth says that the graph of g(x)=x-5+1 is a translation of 5 units to the left and 1 unit up of f(x) = x. She continues to explain that the point (0,0) on the square root function would be translated to the point (-5,1) on the graph of g(x). Is Beth's description of the transformation correct? Explain
<h3>How to determine the true statement?</h3>
The functions are given as:
g(x) = x - 5 + 1
f(x) = x
When the function f(x) is translated 5 units left, we have:
f(x + 5) = x + 5
When the above function is translated 1 unit up, we have:
f(x + 5) + 1 = x + 5 + 1
This means that the actual equation of g(x) should be
g(x) = x + 5 + 1
And not g(x) = x - 5 + 1
By comparison;
g(x) = x - 5 + 1 and g(x) = x + 5 + 1 are not the same
Hence, Beth's description of the transformation is incorrect
Read more about transformation at:
brainly.com/question/17121698
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8/100, 3/5, 7/10
Explanation:
8/100 = 0.08
3/5 = 0.6
7/10 = 0.7
The correct answer is:
[D]: "

" .
__________________________________________________Explanation:__________________________________________________
;
Simplify the "denominator" ; → (b + 2b = 1b + 2b = 3b) ;
and rewrite:

;
Cancel out the "b" in the "numerator" to a "1" ;
and cancel the "3b" in the "denominator to a "3" ;
{since: "b ÷ b = 1 "; and since: "3b ÷ b = 3" } ;
and rewrite as:
____________________________________________________ 
;
____________________________________________________ → which is:
Answer choice: [D]: "
" .
____________________________________________________
The length of AB is 5 units