Answer:
Explanation:
1. Density from mass and volume
![\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}](https://tex.z-dn.net/?f=%5Ctext%7BDensity%7D%20%3D%20%5Cdfrac%7B%5Ctext%7Bmass%7D%7D%7B%5Ctext%7Bvolume%7D%7D%5C%5C%5C%5C%5Crho%20%3D%20%5Cdfrac%7Bm%7D%7BV%7D%5C%5C%5C%5C%5Crho%20%3D%20%5Cdfrac%7B%5Ctext%7B8.6%20g%7D%7D%7B%5Ctext%7B15%20mL%7D%7D%20%3D%20%5Ctext%7B0.57%20g%2FmL%7D%5C%5C%5Ctext%7BThe%20density%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.57%20g%2FmL%7D%7D%24%7D)
2. Volume from density and mass
![V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}](https://tex.z-dn.net/?f=V%20%3D%20%5Ctext%7B9.7%20g%7D%5Ctimes%5Cdfrac%7B%5Ctext%7B1%20mL%7D%7D%7B%5Ctext%7B2.6%20g%7D%7D%20%3D%20%5Ctext%7B3.7%20mL%7D%5C%5C%5C%5C%5Ctext%7BThe%20volume%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B3.7%20mL%7D%7D%24%7D)
3. Mass from density and volume
![\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}](https://tex.z-dn.net/?f=%5Ctext%7BMass%7D%20%3D%20%5Ctext%7B4.1%20cm%7D%5E%7B3%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1.6%20g%7D%7D%7B%5Ctext%7B1%20cm%7D%5E%7B3%7D%7D%20%3D%20%5Ctextbf%7B6.6%20g%7D%5C%5C%5C%5C%5Ctext%7BThe%20mass%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B6.6%20g%7D%7D%24%7D)
4. Density by displacement
Volume of water + object = 24.6 mL
Volume of water =<u> 12.8 mL</u>
Volume of object = 11.8 mL
![\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cdfrac%7B%5Ctext%7B4.3%20g%7D%7D%7B%5Ctext%7B11.8%20mL%7D%7D%20%3D%20%5Ctext%7B0.36%20g%2FmL%7D%5C%5C%5Ctext%7BThe%20density%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.36%20g%2FmL%7D%7D%24%7D)
Your drawing showing water displacement using a graduated cylinder should resemble the figure below.
Answer:
The answer is
<h2>1479.60 mL</h2>
Explanation:
In order to calculate the volume needed we use the formula
![V_2 = \frac{C_1V_1}{C_2}](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BC_1V_1%7D%7BC_2%7D%20)
where
C1 is the concentration of the stock solution
V1 is the volume of the stock solution
C2 is the concentration of the diluted solution
V2 is the volume of thevdiluted solution
From the question
C1 = 1.45 M
V1 = 25 mL
C2 = 0.0245 M
So we have
![V_2 = \frac{1.45 \times 25}{0.0245} = \frac{36.25}{0.0245} \\ = 1479.59...](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B1.45%20%5Ctimes%2025%7D%7B0.0245%7D%20%20%20%3D%20%20%5Cfrac%7B36.25%7D%7B0.0245%7D%20%20%5C%5C%20%20%3D%201479.59...)
We have the final answer as
<h3>1479.60 mL</h3>
Hope this helps you
Answer:
mutation
Explanation:
a mutation in the genes causes cancer cells to reproduce and infect others when it should kill itself off immediately
Answer:
23dm
Explanation:
so you have to do 10g +13dm so the you have to times it by 3 three times