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3 years ago

Please help! I need help on my math grade problem. Please explain if you could

Mathematics

2 answers:

KATRIN_1 [288]3 years ago

7 0

Answer: 3! Hope this helps!

Rus_ich [418]3 years ago

4 0

Answer:

Answer = 3

Step-by-step explanation:

Constant of proportionality = slope

$Slope=\frac{y^{2}-y^{1} }{x^{2}-x^{1} } =\frac{12-9}{4-3}=\frac{3}{1}=3$

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2 years ago

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Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

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3 years ago

Angles A and B are supplementary. Angle A has a measure of 80 degrees. What is the measure of angle B?

Aleonysh [2.5K]

Supplementary angles, when added, equal 180 degrees

so < A + < B = 180...and if < A = 80
80 + < B = 180
< B = 180 - 80
< B = 100 <==

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3 years ago

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