Answer:
the frequency is the fundamental and distance is L = ¼ λ
Explanation:
This problem is a phenomenon of resonance between the frequency of the tuning fork and the tube with one end open and the other end closed, in this case at the closed end you have a node and the open end a belly, so the wavelength is the basis is
λ = 4 L
In this case L = 19.4 cm = 0.194 m
let's use the relationship between wave speed and wavelength frequency and
v = λ f
where the frequency is f = 440 Hz
v = 4 L f
let's calculate
v = 4 0.194 440
v = 341.44 m / s
so the frequency is the fundamental and distance is
L = ¼ λ
Answer:
a) 096V b) 0.0288A c) 0.3456W
Explanation:
a) Vp/Vs= Np/Ns
120/Vs= 500/4
Vs= 096V
b) Np/Ns= Is/Ip
500/4= 3.6/Ip
Ip= 0.0288A
c) P= VI
P=(120)(0.0288)
P= 0.3456W
Electromagnetic force. It is where alike forces ( negative, negative & positive , positive) repel and opposite forces ( negative & positive ) attract.
Hopes this helped
In the sport of volleyball a server is in the "back left position" for standard rules.
Hope I helped,
-CSX :)
It was not the first time that a person who was in a few weeks ago, I
