<span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400
This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.
Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.
Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600
This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.
Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)
The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.
x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>
We have,
- Jane mass is 55 kg
- His body covered with 700 nails all of them having a surface area of 1.00 mm² each = 700 × 1 = 700 mm² = 700/1000000 = 7/10000
We know that,
Let's calculate force as we already have area;
- F = ma
- F = 55 × 9.8 { Acceleration due to gravity }
- F = 539 N
Now, if should she would be on 700 nails then pressure will be;
- P = F/A
- P = 539/7 × 10000
- P = 5390000/7
- P = 770,000 Pascal
And if should would be on a 1 nail only,
- P = F/A
- P = 539/1 × 1000000
- P = 539000000 Pascal
<u>A</u><u>s</u><u>,</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>n</u><u>o</u><u>t</u><u>i</u><u>c</u><u>e</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u>s</u><u>e</u><u>l</u><u>f</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>p</u><u>r</u><u>e</u><u>s</u><u>s</u><u>u</u><u>r</u><u>e</u><u> </u><u>w</u><u>i</u><u>l</u><u>l</u><u> </u><u>b</u><u>e</u><u> </u><u>s</u><u>o</u><u> </u><u>h</u><u>i</u><u>g</u><u>h</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>o</u><u>n</u><u>l</u><u>y</u><u> </u><u>1</u><u> </u><u>n</u><u>a</u><u>i</u><u>l</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>b</u><u>e</u><u>c</u><u>a</u><u>u</u><u>s</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>i</u><u>s</u><u>,</u><u> </u><u>n</u><u>a</u><u>i</u><u>l</u><u> </u><u>w</u><u>i</u><u>l</u><u>l</u><u> </u><u>p</u><u>a</u><u>s</u><u>s</u><u> </u><u>through</u><u> </u><u>j</u><u>a</u><u>n</u><u>e</u><u>'</u><u>s</u><u> </u><u>b</u><u>o</u><u>d</u><u>y</u><u>.</u>
Answer:
the final velocity of the car is 59.33 m/s [N]
Explanation:
Given;
acceleration of the car, a = 13 m/s²
initial velocity of the car, u = 120 km/h = 33.33 m/s
duration of the car motion, t = 2 s
The final velocity of the car in the same direction is calculated as follows;
v = u + at
where;
v is the final velocity of the car
v = 33.33 + 13 x 2
v = 59.33 m/s [N]
Therefore, the final velocity of the car is 59.33 m/s [N]
The amount of heat in the body in joule
Answer:
The value is 
Explanation:
From the question we are told that
The focal length of the objective is 
The focal length of the eyepiece is 
The tube length is 
Generally the magnitude of the overall magnification is mathematically represented as
Where 
is the objective magnification which is mathematically represented as
=> 
=> 
is the eyepiece magnification which is mathematically evaluated as
So
