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3 years ago

PLEASE HEEEEEEELP

Physics

1 answer:

Zepler [3.9K]3 years ago

8 0

<h2> $\large{\underbrace{\underline{\fcolorbox{White}{pink}{\bf{ANSWER♥︎}}}}}$ </h2><h3>kinetic energy is given as</h3>

KE = (0.5) m v²

given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg

KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J

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Explanation:

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4 years ago

The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.11 mm is given by J = (3.

oksano4ka [1.4K]

Answer:

$i = 2.84 \times 10^{-3} A$

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3 years ago

Could I get help please

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I think it’s KE I could be wrong tho

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