PLEASE HEEEEEEELP
1 answer:
<h2>
</h2><h3>kinetic energy is given as</h3>
KE = (0.5) m v²
given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg
KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J
when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J
when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J
when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J
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The vertical movement of the projectile is described by:
y = H - gt² / 2
When the cannonball is on the ground, y= 0 so:
0 = H - gt² /2
Solving for t:
The horizontally movement of the projectile is described by:
x = v₀t
Solving for v₀:
v₀ = x/t
v₀ = 175 m / 2.8 s
v₀ = 61.5 m/s
Answer:
The distance is 300 m.
Explanation:
Given that,
Time = 30 s
Speed = 80 m/s
Distance = 1200 m
Speed of smaller plane = 40 m/s
We need to calculate the acceleration
Using equation of motion
Put the value in the equation
We need to calculate the distance
Using equation of motion
Put the value in the equation
Hence, The distance is 300 m.