All categories

3 years ago

1. An object has a mass of 10g and a volume of 50mL. What is the density?

Physics

1 answer:

Alona [7]3 years ago

7 0

1. 0.2 g/mL

The relationship between mass, density and volume of an object is

$d=\frac{m}{V}$

where

d is the density

m is the mass

V is the volume

For the object in this problem, we have

m = 10 g

V = 50 mL

Substituting into the equation,

$d=\frac{10}{50}=0.2 g/mL$

2. 10 mL

In this exercise we know:

- The density of the object: d = 2 g/mL

- The mass of the object: m = 20 g

Therefore, we can re-arrange the previous equation to find the volume:

$V=\frac{m}{d}$

And substituting values into the equation, we find

$V=\frac{20}{2}=10 mL$

You might be interested in

The relative humidity would be ________% if the actual water vapor in the air was 4 grams per cubic meter, the air's capacity to

AveGali [126]

Answer:

50%

Explanation:

Humidity is the amount water vapor present in the atmosphere.

Relative humidity is defined as the ratio of partial water vapor present in air to the actual water vapor at a particular temperature. It is expressed in percentage and the higher the percentage RH, the more the saturated water vapor present in the atmosphere and vice versa.

It is expressed mathematically as shown;

RH = actual water vapor in air/saturated water vapor × 100%

If the actual water vapor in the air was 4 grams per cubic meter and the air's capacity to hold water vapor was 8 grams per cubic meter

Actual water vapor = 4g/cm³

Air's water capacity (saturated water vapor) = 8g/cm³

RH = 4/8×100

RH = 50%

3 0

3 years ago

Which wave has a wavelengh that is most likely seen as red light?

goblinko [34]

Answer:

Explanation:

Red light has wavelengths around 620 to 750 nm.

7 0

3 years ago

Read 2 more answers

The second minimum in the diffraction pattern of a 0.11-mm-wide slit occurs at 0.72°. What is the wavelength of the light?

Anit [1.1K]

Answer:

691.13 nm

Explanation:

d = width of the slit = 0.11 x 10⁻³ m

θ = angle of diffraction pattern = 0.72° degree

λ = wavelength of the light = ?

m = order = 2 (since second minimum)

for the second minimum diffraction pattern we use the equation

d Sinθ = m λ

Inserting the values

(0.11 x 10⁻³) Sin0.72 = (2) λ

λ = 691.13 x 10⁻⁹ m

λ = 691.13 nm

6 0

3 years ago

A 5.00 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

Brut [27]

Answer:

75 N

Explanation:

In this problem, the position of the crate at time t is given by

$y(t)=2.80t+0.61t^3$

The velocity of the crate vs time is given by the derivative of the position, so it is:

$v(t)=y'(t)=\frac{d}{dt}(2.80t+0.61t^3)=2.80+1.83t^2$

Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:

$a(t)=v'(t)=\frac{d}{dt}(2.80+1.83t^2)=3.66t$ [m/s^2]

According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:

$F(t)=ma(t)$

where

m = 5.00 kg is the mass of the crate

At t = 4.10 s, the acceleration of the crate is

$a(4.10)=3.66\cdot 4.10 =15.0 m/s^2$

And therefore, the force on the crate is:

$F=ma=(5.00)(15.0)=75 N$

7 0

3 years ago

What are the foci of the ellipse given by the equation 100x^2 + 64y^2 = 6 400?

NikAS [45]

The equation of our ellipse is:

$100 x^2 + 64 y^2 = 6400$ (1)

First, let's reduce the equation of the ellipse to the standard form:

$\frac{x^2}{a^2}+ \frac{y^2}{b^2}=1$

To do that, we should divide both terms of equation (1) by 6400, and we get:

$\frac{x^2}{64}+ \frac{y^2}{100}=1$

This is a vertical ellipse (because $b^2 \ \textgreater \ a^2$ ) centered in the origin, and so the distance of its foci from the origin (on the y axis) is given by

$c= \sqrt{b^2-a^2}= \sqrt{(100)-(64)}=6$

Therefore, the position of the two foci is (0,6) and (0,-6)

8 0

4 years ago