Meter #2 is more precise.
There's no information here that tells us which meter is more accurate.
<span>The choices can be found elsewhere and as follows:
</span><span>a. they are so small that they stay close to the ground due to the attractive properties of charged soil particles.
b. they are easily carried by the wind.
c. they easily dissolve in liquid droplets.
d. it is easier for then to roll along the small crevices in the ground.</span><span>
</span>I think the correct answer from the choices listed above is option B. Only the smallest particles of soil can be displaced by suspension because they are so small that they are easily carried by the wind. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Explanation:
There are five equations of motion:
v = at + v₀
Δx = v₀ t + ½ at²
Δx = ½ (v + v₀)t
v² = v₀² + 2aΔx
Δx = vt − ½ at²
Δx is the displacement
v₀ is the initial velocity
v is the final velocity
a is the acceleration
t is time
Thank you for posting your question here at brainly. Below is the solution:
Ke up top = 1/2*.25 *225
<span>gain of Pot energy = .25*9.81*1.2 </span>
<span>work input = (1/4)(2 pi *.6)*30 </span>
<span>so </span>
<span>sum of those 3 energies = </span>
<span>(1/2)(.25)v^2</span>
