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alex41 [277]
3 years ago
6

Which of the following ions is in the lowest oxidation state?

Chemistry
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

B. Cr in Cr_{2}O_{7}^{-2}

Explanation:

Let us first find the oxidation numbers in each of the following scenarios

A. The oxidation number of P in H_{2}PO_{4}^{-} \\ is +5

    because 2H + 4O + P = -1

                    2(1) +4(-2)  + P = -1

                              P = 5

B. The oxidation number of Cr in Cr_{2}O_{7} ]^{-2} \\ is

                 2Cr + 7O = -2

                 2Cr + 7(-2) = -2

                           Cr = 6

C. The oxidation number of Fe in Fe_{2}O_{3} is +3

                          2Fe + 3O = 0

                          2Fe + 3(-2) = 0

                               Fe = 3

The final answer is Cr

bulgar [2K]3 years ago
5 0

Answer:

I believe it is a hope this helps

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Answer:

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\begin{array}{rcl}\dfrac{t_{2}}{t_{1}} & = & \sqrt{\dfrac{M_{2}}{M_{1}}}\\\\\dfrac{t_{2}}{\text{5 s}}& = & \sqrt{\dfrac{44.01}{32.00}}\\\\& = & \sqrt{1.375}\\t_{2}& = & \text{5 s}\times 1.173\\& = & \mathbf{5.9 s} \\\end{array}\\\text{It will take $\large \boxed{\textbf{5.9 s}}$ for the carbon dioxide to effuse.}

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