Answer:
(B) the sum total of all matter and energy
Explanation:
Universe comprises of all the matter and energy that exists in space. It contains billions of stars, planets and interstellar matter that is clouds of dust and gas. There is large amount of the empty space in between.
Universe contains stars as many as grains of sand on all beaches on the Earth. These stars are grouped into galaxies. Milky Way is one of the galaxies. Galaxies can be grouped into clusters and super-clusters.
Answer:
27.82 m/s
Explanation:
The radius of the hose is half of its diameter

So its area must be

The speed of water coming out of the hose is its flow rate divided by the cross-section area of the hose

Answer:
E = 3.04 10⁻⁵ N / C
Explanation:
In this problem we can use the kinematics to find how long it takes the electron to travel the plates
Let's start by reducing the magnitudes to the SI system
vₓ = 5.35 10⁶ m / s
x = 2 cm = 2 10⁻² m
y = 1 cm = 1 10⁻² m
x = vₓ t
t = x / vₓ
t = 2 10⁻² / 5.35 10⁶
t = 3,738 10⁻⁹ s
This time is also the time it takes for vertical movement to go from the center to the plate, let's look for acceleration with Newton's second law
F = m a
a = F / m = e E / m
y =
+ ½ a t²
= 0
We replace
y = ½ e / m E t²
E = 2 y m / e t²
Let's calculate
E = 2 1 10⁻² 9.1 10⁻³¹ / (1.6 10⁻¹⁹ 3,738 10⁻⁹)
E = 18.2 10⁻³³ / 5.98 10⁻²⁸
E = 3.04 10⁻⁵ N / C
Answer: The angle of incidence at which the light will fully be polarized is 60°
Explanation:
To find out the angle of incidence θB for which reflected light is fully polarized we use the equation
n1 sinθB = n2sin(90°− θB) = n 2cosθB
Since n1 is the index of refraction for medium 1 and n2 is the medium of refraction for medium 2 we then solve the equation to get
θB = tan −1 (n2/n1)
= tan −1 (2.22/1.28)=60.0°
Answer:
<em>P = 1500 Watt</em>
Explanation:
<u>Mechanical Work and Power
</u>
Mechanical work is the amount of energy transferred by a force.
Being F the magnitude of the force vector and s the distance, the work is calculated as:
W=F.s
Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.
The power can be calculated as:

Where W is the work and t is the time.
The force to be considered is the weight of the mass of m=100 kg,
:
F = 100 * 10 = 1000 N
The distance is s=3 m, thus the work done by the weight lifter is:
W = 1000 N * 3 m
W = 3000 J
Finally, the power is:

P = 1500 Watt