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7nadin3 [17]
3 years ago
12

How to calculate the mass of hydrated CuSO4

Chemistry
1 answer:
Rus_ich [418]3 years ago
5 0

Hi my dear friend,

How to find mass of hydrate?

Divide the mass of your anhydrous (heated) salt sample by the molar mass of the anhydrous compound to get the number of moles of compound present. In our example, 16 grams / 160 grams per mole = 0.1 moles. Divide the mass of water lost when you heated the salt by the molar mass of water, roughly 18 grams per mole.

~Thank you

You might be interested in
which of these pieces of equipment would be the most appropriate for precisely measuring 29 mL of liquid? Explain your reasoning
Anna007 [38]

Answer:

The best equipment would be the graduated cylinder. Why?

Firstly, the smallest marking on the graduated cylinder is 2 mL, while on all the others the smallest marking is way above that, like 25 mL and 100 mL.

Without even going into the details, we can first rule out the volumetric flask, since its smallest marking is 100 mL and even that is already bigger than our sample size, hence we would have no markings to accurately measure out 29 mL of our sample had we used the volumetric flask.

Next to be ruled out would be the Erlenmeyer flask, as you can see in the image, it only has three marking, and as the smallest marking is 25 mL, each marking is at least 25 mL, and even so far as going up to 50 mL. This cannot let us accurately measure 29 mL out at all, due to the markings being way too big to do that. Hence, the Erlenmeyer flask is ruled out.

Finally, the beaker seems to be a worthy candidate! Unfortunately, for the same reason as the Erlenmeyer flask, as you can see in the image each marking represents 10 mL. We cannot measure 9 mL in the beaker accurately, and hence the beaker is ruled too.

We are left with the graduated cylinder, and that is our answer.

Explanation:

Hope this helped!

5 0
3 years ago
Describe how sodium conducts thermal energy. [3 Marks]
Vera_Pavlovna [14]

In metals, some of the electrons (often one per atom) are not stuck to individual atoms but flow freely among the atoms. Of course, that's why metals are such good conductors of electricity. Now if one end of a bar is hot, and the other is cold, the electrons on the hot end have a little more thermal energy- random jiggling- than the ones on the cold end. So as the electrons wander around, they carry energy from the hot end to the cold end, which is another way of saying they conduct heat.

Here, sodium is a metal which possesses an extra (valence) electron carries the heat around its body as it is a free electron, which enables sodium to conduct thermal energy.

Hope this help :)

3 0
3 years ago
Sugar is stirred into water tp form a solution what names to we give to the sugar and water
Nina [5.8K]
Your answer would be, Sugar is the solute, and water is the solvent. a solution is the mixture of two, or more substances.




Hope that helps!!!
7 0
4 years ago
A graduated cylinder contains 20.0 mL of water. An irregularly shaped object is placed in
RideAnS [48]

Answer:

7.17 g/mL

Explanation:

Density = Mass / Volume

Given mass of object : 80.4g

We are not given the objects volume, however we are given that when put inside of a container with 20.0mL water, the level of the water rises to 31.2 mL.

31.2 - 20 = 11.2

The water level rose 11.2 mL when the object was placed inside of the cylinder containing the water therefore the object has a volume of 11.2mL

Now to find it's density

recall that density = mass / volume

mass = 80.4 and volume = 11.2mL

so density = 80.4/11.2 = 7.17 g/mL

8 0
2 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). If 28
elena-14-01-66 [18.8K]

Answer:

68.1% is percent yield of the reaction

Explanation:

The reaction of methane with oxygen is:

CH₄ + 2O₂ → CO₂ + 2H₂O

<em>Where 2 moles of oxygen react per mole of CH₄</em>

<em />

Percent yield is:

Actual yield (28.2g CO₂) / Theoretical yield * 100

To solve this question we need to find theoretical yield finding limiting reactant :

<em>Moles CH₄:</em>

15.1g CH₄ * (1mol / 16.04g) = 0.9414 moles

<em>Moles O₂:</em>

81.2g * (1mol / 32g) = 2.54 moles

For a complete reaction of 0.9414 moles of CH₄ are needed:

0.9414 moles CH₄ * (2 mol O₂ / 1mol CH₄) = 1.88 moles of O₂. As there are 2.54 moles, O₂ is in excess and <em>CH₄ is limiting reactant</em>

In theoretical yield, the moles of methane added = Moles of CO₂ produced. That is 0.9414 moles CO₂. In grams = Theoretical yield:

0.9414 moles CO₂ * (44.01g / mol) = 41.43g CO₂

Percent yield: 28.2g CO₂ / 41.43g CO₂ * 100=

<h3>68.1% is percent yield of the reaction</h3>
6 0
3 years ago
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