Answer 16. True 17. True 18. False 19. True 20. False
Its electronic confuguration is 2.8.6 so it occupies 3 shells.
Answer:
1 L
Explanation:
V1=P2V2/P1
Checking this, it is correct because P and V at constant T has an inverse relationship.
- Hope that helps! Please let me know if you need further explanation.
You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!
Explanation:
It is known that charge on xenon nucleus is
equal to +54e. And, charge on the proton is
equal to +e. So, radius of the nucleus is as follows.
r = 
= 3.0 fm
Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.
d = r + 2.5
= (3.0 + 2.5) fm
= 5.5 fm
=
(as 1 fm =
)
Therefore, electrostatic repulsive force on proton is calculated as follows.
F = 
Putting the given values into the above formula as follows.
F = 
= 
= 
= 411.2 N
or, =
N
Thus, we ca conclude that
N is the electric force on a proton 2.5 fm from the surface of the nucleus.