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3 years ago

What is the mean for 5 1 15 43 9 9 11 11 14 12 36 and 6 (Use mad)

Mathematics

2 answers:

Tanzania [10]3 years ago

8 0

Answer:

The mean is 14.3

Step-by-step explanation:

d1i1m1o1n [39]3 years ago

3 0

You will have to add all of the numbers up and then divide by how many numbers you see

5+ 1+ 15+ 43+ 9+ 9+ 11+ 11+ 14+ 12+ 36+ 6= 172

Now we will count how many number there are.

there are 12 numbers.

Now we divided 172 and 12 to get the Mean(Average)

We get 14.3333333 as our Mean if we simplify you get 14.3

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I need help with 19 20 21

lord [1]

19) 5c+c=-6+2
6c=-4
c=-4/6
c=-2/3

20) -20-8=-2e
-28=-2e
28/2=e
14=e

21)p-2w=2l
(p-2w)/2=l

5 0

3 years ago

The figure is made up of a cylinder and a sphere which has been cut in half. The radius of each half sphere is 5 mm. What is

alexgriva [62]

<h2>Answer:</h2>

<em>Rounded to the nearest hundredth the volume of the composite figure is:</em>

<em>1308 33 cubic millimeters</em>

<h2>Explanation:</h2>

Hello! I wrote the complete question in a comment above. The volume of a cylinder is defined as:

$V_{c}=\pi r^2 h \\ \\ r:radius \\ \\ h:height$

While the volume of half a sphere is:

$V_{hs}=\frac{2}{3}\pi r^3$

Since we have 2 half spheres, then the volume of these is the same as the volume of a sphere:

$V_{s}=\frac{4}{3}\pi r^3$

Then, the composite figure is:

$V=\pi r^2 h +\frac{4}{3}\pi r^3 \\ \\ V=\pi r^2(h+\frac{4}{3}r)$

The radius of the cylinder is the same of the radius of each half sphere. So:

$r=5mm \\ \\ h=10mm \\ \\ \\ V=(3.14) (5)^2((10)+\frac{4}{3}(5)) \\ \\ V=25(3.14)(10+\frac{20}{3}) \\ \\ \boxed{V\approx 1308.33mm^3}$

7 0

3 years ago

Matt gave 5 apples to his son and sold 8 times as many apples. If Matt had 1/2 of the apples left, how many did he have in the b

Gala2k [10]

Answer:

Step-by-step explanation:

8*5 = 40

40 + 5 = 45

1/2 x = 45

x = 90

4 0

3 years ago

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While baking, Pedro used

ehidna [41]

Answer:

11 cups of flour..... any other questions?

Step-by-step explanation:

6 0

3 years ago

What is the area of a cross section that is parallel to face CDHG ?

Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

$Length\times breadth\\\\=36\times 12\\\\=432\ cm^2$

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0

3 years ago

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